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You are no less than Ron ...I would rate you above them in Maths I mean what great explanations....... can you fw the links of your blog on MODULUS, various type of questions..... Thanks a trillion....I am sure i have added atleast 1 point to my maths score.......

Was it so simple!!!!!!!!I am thinking now!!!!!!!!!!!!!!!!!!!! Waiting for links on modulus!!!!!!!!!!!!!

Thank you for the book, it is a very useful one. I have a question on Solving equations of degree 2 : QUADRATIC part. "The sum is -11 and the product is 30. So numbers are -5,-6". I think there is a typo: the sum is 11 (=b), not -11 as far as the solutions are x1=-5, and x2=-6 (we have 2 binomials (x+5) and (x+6). Please correct if I am wrong. Thanks again.

Thank you for the book, it is a very useful one. I have a question on Solving equations of degree 2 : QUADRATIC part. "The sum is -11 and the product is 30. So numbers are -5,-6". I think there is a typo: the sum is 11 (=b), not -11 as far as the solutions are x1=-5, and x2=-6 (we have 2 binomials (x+5) and (x+6). Please correct if I am wrong. Thanks again.

The sum of the roots is (-5) + (-6) = -11, which is -b/a=-(11/1)=-11.

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

Eg. \(x^6 -3x^3 + 2 = 0\) Here let \(y=x^3\) \(y^2-3y+2=0\) \((y-2)(y-1)=0\)

So the solution is y=1,2 or x^3=1,2 or x=1,cube_root(3)

Hi,

First of all, numerous thanks for all the work on this forum, it is so helpful.

I was going through the Math book and noticed a typo on the solution above. Shouldn't x = 1 & cube_root(2) ? Not a big deal, but always worth mentioning!

Eg. \(x^6 -3x^3 + 2 = 0\) Here let \(y=x^3\) \(y^2-3y+2=0\) \((y-2)(y-1)=0\)

So the solution is y=1,2 or x^3=1,2 or x=1,cube_root(3)

Hi,

First of all, numerous thanks for all the work on this forum, it is so helpful.

I was going through the Math book and noticed a typo on the solution above. Shouldn't x = 1 & cube_root(2) ? Not a big deal, but always worth mentioning!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

Check out this awesome article about Anderson on Poets Quants, http://poetsandquants.com/2015/01/02/uclas-anderson-school-morphs-into-a-friendly-tech-hub/ . Anderson is a great place! Sorry for the lack of updates recently. I...