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Max (x,y) is defined as the maximum of x and y, and min(x,y)

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Max (x,y) is defined as the maximum of x and y, and min(x,y) [#permalink] New post 28 Feb 2012, 18:52
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Max (x,y) is defined as the maximum of x and y, and Min(x,y) is defined as the minimum of x and y. What is the average of Max(x,60) and Min(40,x) ?

(1) Min(x, 60) = x
(2) Max(40, x) = x



guys my question is how to rephrase this question and consider the possible values of x
i have considered the possible values of x
if x>60 then max(x,60)=x and min(40,x)=40
if x<40 then max(x,60)=60 and min(40,x)=x
if 40<x<60 then max(x,60)= 60 and min(40,x) =x


i have doubt in last two considered values.
[Reveal] Spoiler: OA

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Re: Max (x,y) is defined as the maximum of x and y, and min(x,y) [#permalink] New post 28 Feb 2012, 22:32
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GMATD11 wrote:
Max (x,y) is defined as the maximum of x and y, and Min(x,y) is defined as the minimum of x and y. What is the average of Max(x,60) and Min(40,x) ?

(1) Min(x, 60) = x
(2) Max(40, x) = x



guys my question is how to rephrase this question and consider the possible values of x
i have considered the possible values of x
if x>60 then max(x,60)=x and min(40,x)=40
if x<40 then max(x,60)=60 and min(40,x)=x
if 40<x<60 then max(x,60)= 60 and min(40,x) =x


i have doubt in last two considered values.


First of all: max(x,y) and min(x,y) are just some functions defined as: max(x,y)=the maximum of x and y and min(x,y)=the minimum of x and y.

Max (x,y) is defined as the maximum of x and y, and Min(x,y) is defined as the minimum of x and y. What is the average of Max(x,60) and Min(40,x) ?

Question is: average=\frac{min(40,x)+max(x,60)}{2}=?. Consider the following three cases:

If x<{40} then min(40,x)=x, max(x,60)=60 and average=\frac{x+60}{2}=?;
If 40<x<60 then min(40,x)=40, max(x,60)=60 and average=\frac{40+60}{2}=50;
If x>{60} then min(40,x)=40, max(x,60)=x and average=\frac{40+x}{2}=?.

(1) Min(x,60)=x --> just says that x<60, so we have either the first or the second case. Not sufficient.

(2) Max(40,x)=x --> just says that x>40, so we have either the second or the third case. Not sufficient.

(1)+(2) 40<x<60 so we have the second case: min(40,x)=40, max(x,60)=60 and average=\frac{40+60}{2}=50. Sufficient.

Answer: C.

Hope it helps.

P.S. You could just plug some different values of x to get the three cases, for example: x=30<40, 40<(x=50)<60 and x=70>60.
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Senior Manager
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Joined: 10 Nov 2010
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Re: Max (x,y) is defined as the maximum of x and y, and min(x,y) [#permalink] New post 28 Feb 2012, 23:56
Thanks

Can we consider X<=40 & 40<=X<=60
Explanation takes these kind of values
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Re: Max (x,y) is defined as the maximum of x and y, and min(x,y) [#permalink] New post 29 Feb 2012, 00:04
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Re: Max (x,y) is defined as the maximum of x and y, and min(x,y) [#permalink] New post 14 Jun 2013, 03:04
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Bumping for review and further discussion*. Get a kudos point for an alternative solution!

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RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

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Re: Max (x,y) is defined as the maximum of x and y, and min(x,y)   [#permalink] 14 Jun 2013, 03:04
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