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Maybe not that tricky for you all. A dude wants to

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Maybe not that tricky for you all. A dude wants to [#permalink] New post 16 Jul 2007, 09:10
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Maybe not that tricky for you all.

A dude wants to fencing a rectangular area. One of the side is 50 fleet, which he already fenced. He has 80 ft left in fencing. What is the other side must he built to maxime area.

Anyone got any question on how to solve this one?

Dan
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Re: PS question tricky [#permalink] New post 16 Jul 2007, 09:14
dragonball20cal wrote:
Maybe not that tricky for you all.

A dude wants to fencing a rectangular area. One of the side is 50 fleet, which he already fenced. He has 80 ft left in fencing. What is the other side must he built to maxime area.

Anyone got any question on how to solve this one?

Dan


If the fenced area has to be rectangular then the only option he has is to make the other side (80-50)/2 = 15 ft.

But this solution definitely does not make the problem tricky. :) So what am I missing ?? :?
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ps tricky [#permalink] New post 16 Jul 2007, 13:55
what if it is doesn't have to be rectegular?

how do you maxmize area of qualiteral.

is the square the optiomal maximizer?

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 [#permalink] New post 16 Jul 2007, 16:13
that's it the square maximize the area.
so maybe each the remaining side should have the same lenght? 80/3
  [#permalink] 16 Jul 2007, 16:13
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