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Mean+Median+Mode

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Joined: 02 Sep 2008
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Mean+Median+Mode [#permalink] New post 14 Mar 2009, 18:26
What is the median number of employees assigned per project for the projects at
Company Z?
(1) 25 percent of the projects at Company Z have 4 or more employees assigned to
each project.
(2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to
each project.
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is
sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
Senior Manager
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Joined: 06 Mar 2006
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Re: Mean+Median+Mode [#permalink] New post 15 Mar 2009, 08:00
milind1979 wrote:
What is the median number of employees assigned per project for the projects at
Company Z?
(1) 25 percent of the projects at Company Z have 4 or more employees assigned to
each project.
(2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to
each project.
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is
sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.


Statement 1 only tells you that 25% of the projects have 4 or more employees assigned, which means 75% of the projects will have less than 4 employees. Therefore, insufficient.
Statement 2 only tells you that 35% of the projects have 2 or fewer employees assigned, which means 65% of the projects will have greater than 2 employees. Therefore, insufficient.
Together, combine the two statement you know that 40% of the projects will have 3 employees assigned to each project. Therefore, 3 is your median. Sufficient.

Answer C
Re: Mean+Median+Mode   [#permalink] 15 Mar 2009, 08:00
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Mean , Median and mode.......... milind1979 1 03 May 2009, 20:10
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