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Median/Mean/Set Problem - DS

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Median/Mean/Set Problem - DS [#permalink] New post 16 May 2007, 18:05
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How would you solve?

What is the median value of the set R, if for every term in the set, Rn = Rn–1 + 3?

(1) The first term of set R is 15.

(2) The mean of set R is 36.
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Re: Median/Mean/Set Problem - DS [#permalink] New post 16 May 2007, 18:39
above720 wrote:
How would you solve?

What is the median value of the set R, if for every term in the set, Rn = Rn–1 + 3?

(1) The first term of set R is 15.

(2) The mean of set R is 36.


(B) it is

AP here so the mean = the median.
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Re: Median/Mean/Set Problem - DS [#permalink] New post 16 May 2007, 19:00
kirakira wrote:
above720 wrote:
How would you solve?

What is the median value of the set R, if for every term in the set, Rn = Rn–1 + 3?

(1) The first term of set R is 15.

(2) The mean of set R is 36.


(B) it is

AP here so the mean = the median.


thanks kirakira i didn't know that for AP the median = the mean
I learned something new today :-D
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Re: Median/Mean/Set Problem - DS [#permalink] New post 18 May 2007, 21:53
above720 wrote:
How would you solve?

What is the median value of the set R, if for every term in the set, Rn = Rn–1 + 3?

(1) The first term of set R is 15.
(2) The mean of set R is 36.


little tricky but agree with B because it is AP..
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 [#permalink] New post 21 May 2007, 16:13
Can someone please tie in AP with the answer choice of B.? Thanks.
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 [#permalink] New post 21 May 2007, 20:03
The way AP ties into this question is because if you look at the question R(n) = R(n-1) + 3 which means that each term is + plus the previous term, this signifies that the series is an arithmetic progression (AP) meaning that there is an additive term 3 with each following term.
Having established this, the concept that the mean of an AP is the median answers the question
  [#permalink] 21 May 2007, 20:03
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