abhijit_sen wrote:

1) 2 > 1 also 4 > 1

5 > 3 also 25 > 1

0 > -1

This statement will always hold true. So question can be answer hence answer should be A or D.

2) x^3 > y.

(4)^3 > 5 but 4 < 5 (counter case for statement 2)

(5)^3 > 4 also 5 > 4 (supporting statement 2)

Thereby Maybe case so on basis of B question cannot be answered.

So answer is A.

your are only taking interger values. If you take value of x between 0 and 1. then A is not suff.

Is x > y?

(1) SQRT(X)> y

(2) x^3 > y

1) x > y^2

2) x^3 > y

from 1, X can be 'integere/improper fraction ( X can be any value more than 1)' more than Y or X can be a proper fraction greater than Y

from 2, X can be 'integere/improper fraction ( X can be any value more than 1)' greater than Y or X can be a proper fraction less than Y.

adding together, X is a 'integere/improper fraction ( X can be any value more than 1)' more than Y

IMO C