Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 03 Jun 2015, 10:08

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Micheal and Adam can do together a piece of work in 20 days.

Author Message
TAGS:
Director
Joined: 05 Jan 2008
Posts: 707
Followers: 3

Kudos [?]: 153 [0], given: 0

Micheal and Adam can do together a piece of work in 20 days. [#permalink]  11 Mar 2008, 03:47
2
This post was
BOOKMARKED
00:00

Difficulty:

15% (low)

Question Stats:

84% (02:50) correct 16% (02:10) wrong based on 160 sessions
Micheal and Adam can do together a piece of work in 20 days. After they have worked together for 12 days Micheal stops and Adam completes the remaining work in 10 days. In how many days Micheal complete the work separately.

A. 80 days
B. 100 days
C. 120 days
D. 110 days
E. 90 days
[Reveal] Spoiler: OA

_________________

Persistence+Patience+Persistence+Patience=G...O...A...L

Last edited by Bunuel on 24 Feb 2014, 12:28, edited 1 time in total.
Renamed the topic, edited the question, added the OA and moved to PS forum.
Director
Joined: 10 Sep 2007
Posts: 949
Followers: 7

Kudos [?]: 208 [1] , given: 0

Re: Time & Work-2 [#permalink]  11 Mar 2008, 06:06
1
KUDOS
Suppose rate of work for per day Mike = M & Rate of work per day for Adam = A
Together in a Day they can finish = A + M units
Total Work Done in 20 Days = 20(A+M)
Total Work Done in 12 Days = 12(A+M)
Work Done by Adam in 10 Days = 10A

Since total work is same we can say that 20(A+M) = 12(A+M) + 10A => 8M = 2A => A = 4M
So total work done by them together in 20 Days = 20(4M+M) = 100M
Since Mike does M unit of work per day, it will take him 100 Days to finish up the work.

Director
Status: No dream is too large, no dreamer is too small
Joined: 14 Jul 2010
Posts: 661
Followers: 37

Kudos [?]: 368 [6] , given: 39

Re: Time & Work-2 [#permalink]  30 Nov 2011, 20:49
6
KUDOS
Rate of both = 1/20
Together they do = 1/20*12 = 3/5

Left work = 1 - 3/5 = 2/5

Adam completes 2/5 work in 10 day
so he took 10*5/2 = 25 days to complete the left work alone.
Thus the rate of adam is 1/25

Rate of Micheal = 1/20 - 1/25 = 1/100
Thus micheal takes 100 days to complete the whole work.
ans. B.
_________________

Collections:-
PSof OG solved by GC members: http://gmatclub.com/forum/collection-ps-with-solution-from-gmatclub-110005.html
DS of OG solved by GC members: http://gmatclub.com/forum/collection-ds-with-solution-from-gmatclub-110004.html
100 GMAT PREP Quantitative collection http://gmatclub.com/forum/gmat-prep-problem-collections-114358.html
Collections of work/rate problems with solutions http://gmatclub.com/forum/collections-of-work-rate-problem-with-solutions-118919.html
Mixture problems in a file with best solutions: http://gmatclub.com/forum/mixture-problems-with-best-and-easy-solutions-all-together-124644.html

Director
Status: No dream is too large, no dreamer is too small
Joined: 14 Jul 2010
Posts: 661
Followers: 37

Kudos [?]: 368 [1] , given: 39

Re: Time & Work-2 [#permalink]  18 Dec 2011, 09:24
1
KUDOS
I got another way of the same problem
1/20*12+10x=1 [Rate of Adam is x]
x = 1/25
so, rate of Micheal =1/20-1/25 = 1/100

So Micheal take 100 days
Ans. B
_________________

Collections:-
PSof OG solved by GC members: http://gmatclub.com/forum/collection-ps-with-solution-from-gmatclub-110005.html
DS of OG solved by GC members: http://gmatclub.com/forum/collection-ds-with-solution-from-gmatclub-110004.html
100 GMAT PREP Quantitative collection http://gmatclub.com/forum/gmat-prep-problem-collections-114358.html
Collections of work/rate problems with solutions http://gmatclub.com/forum/collections-of-work-rate-problem-with-solutions-118919.html
Mixture problems in a file with best solutions: http://gmatclub.com/forum/mixture-problems-with-best-and-easy-solutions-all-together-124644.html

GMAT Club Legend
Joined: 09 Sep 2013
Posts: 5009
Followers: 301

Kudos [?]: 55 [0], given: 0

Re: Micheal and Adam can do together a piece of work in 20 days. [#permalink]  24 Feb 2014, 12:23
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1856
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)
Followers: 22

Kudos [?]: 906 [0], given: 193

Re: Micheal and Adam can do together a piece of work in 20 days. [#permalink]  13 Mar 2014, 23:33
Both have completed $$\frac{12}{20}$$ work, means $$\frac{8}{20}$$ work is pending

Adam completed $$\frac{8}{20}$$ work in 10 days

Rate of Adam = $$\frac{8}{(20 * 10)} = \frac{8}{200}$$

So, rate of Michael = $$\frac{1}{20} - \frac{8}{200}$$

= $$\frac{2}{200}$$

= $$\frac{1}{100}$$

So Michael completes the work in 100 Days

_________________

Kindly press "+1 Kudos" to appreciate

Intern
Joined: 05 Mar 2014
Posts: 9
Followers: 0

Kudos [?]: 0 [0], given: 100

Re: Micheal and Adam can do together a piece of work in 20 days. [#permalink]  29 Mar 2014, 09:41
I`ve done in 5 steps:

1 - M+A = X/20 where X is arbitrarily 100, so M+A rate is 5/day of a total of 100.

2 - (M+A) *12 = 60. 100-60 = 40

3 - A completed 40 in 10 days, so 4/day.

4 - M+A = 5, M + 4 = 5, M = 1.

5 - 1 (rate) * 100(total work) = 100 days
Re: Micheal and Adam can do together a piece of work in 20 days.   [#permalink] 29 Mar 2014, 09:41
Similar topics Replies Last post
Similar
Topics:
1 P,Q and R can do a piece of work in 4,6 and 12 days working 1 23 Oct 2013, 10:50
9 Matt and Peter can do together a piece of work in 20 days 14 11 Mar 2008, 02:56
A and B together can do a peace of work in 12 days,which B 13 05 Feb 2007, 10:30
A and B together can do a piece of work in 72/5 days ; B and 1 08 Oct 2006, 03:37
Working together, A and B can do a job in 6 days. B and C 6 29 Oct 2005, 09:21
Display posts from previous: Sort by