Micheal and Adam can do together a piece of work in 20 days.

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Micheal and Adam can do together a piece of work in 20 days. [#permalink]

11 Mar 2008, 04:47

Micheal and Adam can do together a piece of work in 20 days. After they have worked together for 12 days Micheal stops and Adam completes the remaining work in 10 days. In how many days Micheal complete the work separately.

80 days

100 days

120 days

110 days

90 days
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Re: Time & Work-2 [#permalink]

11 Mar 2008, 07:06

Suppose rate of work for per day Mike = M & Rate of work per day for Adam = A
Together in a Day they can finish = A + M units
Total Work Done in 20 Days = 20(A+M)
Total Work Done in 12 Days = 12(A+M)
Work Done by Adam in 10 Days = 10A

Since total work is same we can say that 20(A+M) = 12(A+M) + 10A => 8M = 2A => A = 4M
So total work done by them together in 20 Days = 20(4M+M) = 100M
Since Mike does M unit of work per day, it will take him 100 Days to finish up the work.

Answer B.

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Re: Time & Work-2 [#permalink]

30 Nov 2011, 21:49

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Rate of both = 1/20
Together they do = 1/20*12 = 3/5

Left work = 1 - 3/5 = 2/5

Adam completes 2/5 work in 10 day
so he took 10*5/2 = 25 days to complete the left work alone.
Thus the rate of adam is 1/25

Rate of Micheal = 1/20 - 1/25 = 1/100
Thus micheal takes 100 days to complete the whole work.
ans. B.
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Director

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Joined: 14 Jul 2010

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Re: Time & Work-2 [#permalink]

18 Dec 2011, 10:24

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KUDOS

I got another way of the same problem
1/20*12+10x=1 [Rate of Adam is x]
x = 1/25
so, rate of Micheal =1/20-1/25 = 1/100

So Micheal take 100 days
Ans. B
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Re: Time & Work-2 [#permalink] 18 Dec 2011, 10:24

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Micheal and Adam can do together a piece of work in 20 days.

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Micheal and Adam can do together a piece of work in 20 days.

Micheal and Adam can do together a piece of work in 20 days.

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