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Mike and Sue are running toward each other. The ratio [#permalink]
 18 Oct 2006, 02:16
3. Mike and Sue are running toward each other. The ratio between Mike’s speed and Sue's speed is 4 to 7 and the distance between them is 352 meters. What is the distance Sue passed?
(A) 96m (B) 128m (C) 222m (D) 224m (E) 312m
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Director
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Re: Rate and Ratio Combo Question. [#permalink]
18 Oct 2006, 03:47
ishtmeet wrote: 3. Mike and Sue are running toward each other. The ratio between Mike’s speed and Sue's speed is 4 to 7 and the distance between them is 352 meters. What is the distance Sue passed?
(A) 96m (B) 128m (C) 222m (D) 224m (E) 312m
What this question is asking for? Is it written this way originally?
Last edited by SimaQ on 18 Oct 2006, 04:02, edited 1 time in total.
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Director
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I suppose it asks for number of meters Sue has covered when she met Mike...
I would pick B....
I am sure there are some shortcurts to solving this, but i take the definite way  my approach took me around 2 min....
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Director
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My answer is D. What is the OA?
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Director
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Yes D.... I did not complete my calculations.... that is, 352-128=224... have to stop rushing things....
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Director
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My solving:
Creating the table
Sue: rate= 7/1, time=t, distance=d
Mike: rate= 4/1, time=t, distance=352-d
Make two eqation:
7/1t=d
4/1t=352-d.....replace d with 7/1t
4/1t=352-7/1t
4/1t+7/1t=352
11/1t=352
t=32
To know what distance Sue has covered when she met Mike simply use r*t=d formula.
7/1*32=d
d=224.
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Intern
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Time = Distance/speed
They would hav spent same amount of time when they meet,
lets say mike ran x m and sue ran 352-x m, let m and be their respective speeds
so
x/m = (352-x)/s
x/(352-x) = m/s
x/(352-x) = 4/7 (putting the speed ratio)
x = 128
352-128 = 224
D
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Director
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Should be B.
Total relative speed is 11 units. She would have covered
4*352/11 = 128 m
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Director
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Didn't rewrite the question, as I should have done. It is
7*352/11 = 224
D is the correct answer.
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Yes (D) ..since their speed ratios are 4:7 hence Sue covers 7*(352)/11=224
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