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mixture problem

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shrive555
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mixture problem [#permalink] New post   09 Jun 2011, 22:46
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Ten grams of sugar are added to a 40-g serving of a breakfast cereal that is 30% sugar. What is the percent concentration of sugar in the resulting mixture?



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Re: mixture problem [#permalink] New post   10 Jun 2011, 02:40
originally 40 gms of cereal contains 30% sugar. so original amount of sugar = 30/100 * 40 = 12 gram. Now additional 10 grams of sugar is added. so resulting mixture has 22 grams of sugar our of (40 +10) =50 gram mixture.

22grm out of 50grams = 44 % (x/100 % * 50 =22, so x =44 %)
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Re: mixture problem [#permalink] New post   10 Jun 2011, 03:21
i think that is an easy stuff.
regards.
thanks for nice explanation.
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Re: mixture problem [#permalink] New post   10 Jun 2011, 04:36
The quantity of sugar present originally in the mixture = 30/100 * 40 grams = 12 grams

So now Total sugar after adding 10 grams = (12 + 10) grams = 22 grams


Total quantity of mixture after adding the sugar = (40 + 10) grams = 50 grams


Hence percentage concentration = 22/50 * 100 = 44 %
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Re: mixture problem [#permalink] New post   10 Jun 2011, 04:55
% of sugar = \(((0.3*40 + 10)/50)*100\)= 44%
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Re: mixture problem [#permalink] New post   10 Jun 2011, 11:18
Easy !!! 44% like Subhashghosh correctly explained



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Re: mixture problem [#permalink]
10 Jun 2011, 11:18
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