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VP
Joined: 08 Jun 2005
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Mixture Problems Made Easy [#permalink]
02 Aug 2007, 15:24
35
This post received KUDOS
Mixture problems made Easy
solving mixture problems fast ! - (30 day money back guarantee  )
see attachment
Thanks
Last edited by KillerSquirrel on 31 Aug 2007, 00:25, edited 2 times in total.
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Manager
Joined: 17 May 2007
Posts: 73
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thanks for sharing
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Manager
Joined: 27 May 2007
Posts: 129
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Thank you for posting that! It's much easier than the way I was solving mixtures.
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VP
Joined: 08 Jun 2005
Posts: 1172
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2
This post received KUDOS
You are all welcome !
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Senior Manager
Joined: 24 Nov 2006
Posts: 353
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KillerSquirrel wrote: You are all welcome ! 
Great contribution, thank you KillerSquirrel
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Director
Joined: 12 Jul 2007
Posts: 875
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awesome page! thanks!
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Intern
Joined: 06 Aug 2007
Posts: 39
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Excellent page, makes these things appear a lot simple!
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Intern
Joined: 07 Aug 2007
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Wow, that was awesome. Do you have anything like that for... [#permalink]
09 Aug 2007, 03:56
inequalities and ultimate values? These 2 have been a huge issue for me.
Thanks for posting that - it's going to help a lot!
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Intern
Joined: 17 Jan 2010
Posts: 31
Schools: SSE, LSE
Followers: 0
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Re: Mixture Problems Made Easy [#permalink]
06 Mar 2010, 10:44
So far this questions gave me a hard time!!Great tool!!Thanks
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Senior Manager
Joined: 12 May 2010
Posts: 292
Location: United Kingdom
Concentration: Entrepreneurship, Technology
GMAT Date: 10-22-2011
GPA: 3
WE: Information Technology (Internet and New Media)
Followers: 4
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26
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Re: Mixture Problems Made Easy [#permalink]
09 Jul 2010, 04:40
once you get the hang of these questions and practice a few they are pretty straightforward. The trick is trying to work out what the question is getting at!
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Intern
Affiliations: USMA
Joined: 09 Apr 2010
Posts: 21
Location: DC
Schools: Columbia, NYU, Dartmouth, Darden
WE 1: Army
WE 2: Consultant
Followers: 0
Kudos [?]:
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Re: Mixture Problems Made Easy [#permalink]
16 Jul 2010, 07:17
one of the best posts on the website - thanks a lot. This makes these problems like child's play. I wouldn't be surprised if some company TMs this technique if hasn't already.
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Senior Manager
Status: Time to step up the tempo
Joined: 24 Jun 2010
Posts: 420
Location: Milky way
Schools: ISB, Tepper - CMU, Chicago Booth, LSB
Followers: 6
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Re: Mixture Problems Made Easy [#permalink]
16 Jul 2010, 19:08
Thanks for sharing... this is very helpful....
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Manager
Joined: 27 Jun 2010
Posts: 55
Location: India
WE 1: 1 Year Research & Development
WE 2: 7.5 Years IT Consultant
Followers: 0
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Re: Mixture Problems Made Easy [#permalink]
19 Jul 2010, 21:06
Thanks for the wonderful method.
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Intern
Affiliations: ACCA
Joined: 17 Apr 2010
Posts: 34
Schools: IMD, Insead, LBS, IE, Cambridge, Oxford
Followers: 0
Kudos [?]:
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Re: Mixture Problems Made Easy [#permalink]
23 Jul 2010, 15:19
Thanks good job! Posted from my mobile device
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Manager
Joined: 16 Feb 2010
Posts: 236
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Re: Mixture Problems Made Easy [#permalink]
25 Jul 2010, 08:33
thanks
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Manager
Joined: 12 Jun 2010
Posts: 65
Followers: 1
Kudos [?]:
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Re: Mixture Problems Made Easy [#permalink]
25 Jul 2010, 21:17
thanks. This was a great help.
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Manager
Joined: 12 Jun 2010
Posts: 65
Followers: 1
Kudos [?]:
1
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Re: Mixture Problems Made Easy [#permalink]
25 Jul 2010, 21:18
thanks. This was a great help.
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Intern
Joined: 15 Jan 2010
Posts: 2
Location: TORONTO
Followers: 0
Kudos [?]:
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Re: Mixture Problems Made Easy [#permalink]
26 Jul 2010, 04:58
great quick process - thanks
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VP
Status: Current Student
Joined: 24 Aug 2010
Posts: 1295
Location: United States
GMAT 1: 710 Q48 V40
WE: Sales (Consumer Products)
Followers: 74
Kudos [?]:
366
[0], given: 71
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Re: Mixture Problems Made Easy [#permalink]
23 Sep 2010, 15:45
Quick question. In the Example 5, the explanation says that the volume of the new solution is x/2. If one amount of solution replaces the same amount, how is the volume of the new solution cut in half? If I take out 1 liter of solution and replace it with 1 liter of another solution, my overall volume stays the same. Could someone please explain the assumption that the volume is x/2. Thanks!
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Intern
Joined: 28 Oct 2010
Posts: 1
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Re: Mixture Problems Made Easy [#permalink]
28 Oct 2010, 07:54
gr8 post!
but can anyone show me how to solve this problem , with the method given here
Question: 10kg of a mixture contains 30% sand and 70% clay. In order to make the mixture contain equal quantities of clay and sand. how much of the mixture is to be removed and replaced with pure sand?
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Re: Mixture Problems Made Easy
[#permalink]
28 Oct 2010, 07:54
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