tkarthi4u wrote:

If a portion of a half water/half alcohol mix is replaced with 25% alcohol solution, resulting in a 30% alcohol solution, what percentage of the original alcohol was replaced?

Can you please explain?

Well, there are no Answer options, eh! Anyways, according to me, the answer is 80% or 4/5th of the original mix was replaced.

Using amalgamation,

50--------------25

--------30--------

5---------------20

ie : 5:20 => 1:4.

But I am not sure what "percentage of Original alcohol was replaced" means. If I did get it right, the answer for alcohol automatically comes out to be the same ie 80% or 4/5th.

What is the OA?

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