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# Month - June, July August Number of days worked -

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Month - June, July August Number of days worked - [#permalink]

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02 Jan 2006, 20:01
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Month - June, July August

Number of days worked - 20(June), 17(July), 19 (Aug)

The table above shows the number of days worked by a certain sales representative in each of three months last year. If the number of sales calls that the representative made each month was proportional to the number of days worked in that month and if the representative made a total of 168 sales calls in the three months shown, how many sales calls did the representative make in August?

A. 50
B. 51
C. 56
D. 57
E. 60

Can someone explain the proportion concept? Thanks.
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JAI HIND!

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02 Jan 2006, 20:07
D?

Let k be the multipilying factor (proportationality constant) for getting the actual number of calls.

20k+17k+19k = 168
k = 3

=> num of calls in August = 3*19 = 57
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03 Jan 2006, 00:24
JAI HIND wrote:
Month - June, July August

Number of days worked - 20(June), 17(July), 19 (Aug)

The table above shows the number of days worked by a certain sales representative in each of three months last year. If the number of sales calls that the representative made each month was proportional to the number of days worked in that month and if the representative made a total of 168 sales calls in the three months shown, how many sales calls did the representative make in August?

A. 50
B. 51
C. 56
D. 57
E. 60

Can someone explain the proportion concept? Thanks.

Given that 20X+17X+19X = 168 where X is the proportionality factor.
56X=168 => X=3
No of days sr worked in aug = 19, hence 19*3 = 57 calls were made in Aug.
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03 Jan 2006, 09:14
D for me . Ratio of calls made each month is 20:17:19 = 57

=168/56 *19 for august.
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Tony Chandra

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03 Jan 2006, 22:06
D for me too

S1:S2:S3= 20:17:19=> 19/56*168=57
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04 Jan 2006, 04:56
# of calls each month was proportional to the # of days worked.

20n+17n+19n = 168
n =168/(20+17+19) = 3

# of sales calls made in Aug = 19*3 = 57
04 Jan 2006, 04:56
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