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# Mr. and Mrs. Wiley have a child every J years. Their oldest

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Mr. and Mrs. Wiley have a child every J years. Their oldest [#permalink]  06 Feb 2010, 12:17
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Question Stats:

59% (02:33) correct 41% (01:32) wrong based on 63 sessions
Mr. and Mrs. Wiley have a child every J years. Their oldest child is now T years old. If they have a child 2 years from now, how many children will they have in total?

(A) \frac{T+2}{J} + 1

(B) JT + 1

(C) \frac{J}{T} + \frac{1}{T}

(D) TJ - 1

(E) \frac{T+J}{J}

Source: Manhattan Guide

[Reveal] Spoiler: OA

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Last edited by Bunuel on 22 Nov 2012, 04:41, edited 1 time in total.
Renamed the topic and edited the question.
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Re: Mr. and Mrs Wiley, VIC [#permalink]  21 Nov 2012, 09:45
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Expert's post
jeeteshsingh wrote:
Need the solution using Algebra....

Mr. & Mrs Wiley have a child every J years. Their oldest child is now T years old. If they have a child 2 years from now, how many children will they have in total?

(A) \frac{T+2}{J} + 1

(B) JT + 1

(C) \frac{J}{T} + \frac{1}{T}

(D) TJ - 1

(E) \frac{T+J}{J}

[Reveal] Spoiler: OA:
(A)

Source: Manhattan Guide

Think of it as an Arithmetic Progression where every subsequent term (child) has a difference of J yrs from the previous term (child).

1st child, 2nd child, 3rd child, ....... nth child (to be born after 2 yrs)

What is the difference between first and last terms (children)? (T + 2) yrs

What is the common difference (age difference between two consecutive kids)? J yrs

What is the number of terms (children)? (T + 2)/J + 1
(Number of terms of an AP is n = (Last term - First term)/Common Difference + 1. )
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Save $100 on Veritas Prep GMAT Courses And Admissions Consulting Enroll now. Pay later. Take advantage of Veritas Prep's flexible payment plan options. Veritas Prep Reviews Senior Manager Joined: 25 Jun 2009 Posts: 313 Followers: 2 Kudos [?]: 70 [0], given: 6 Re: Mr. and Mrs Wiley, VIC [#permalink] 06 Feb 2010, 12:35 jeeteshsingh wrote: Need the solution using Algebra.... Mr. & Mrs Wiley have a child every J years. Their oldest child is now T years old. If they have a child 2 years from now, how many children will they have in total? (A) \frac{T+2}{J} + 1 (B) JT + 1 (C) \frac{J}{T} + \frac{1}{T} (D) TJ - 1 (E) \frac{T+J}{J} [Reveal] Spoiler: OA: (A) Source: Manhattan Guide Please give the algebric solution. Lets take it this way, They had first child today, after J years they will have 2nd child, and again after J years they will have 3rd child.. And now according to the Q stem in T + 2 years they will have J kids Hence number kids in T + 2 years = T+2 /J We will have to add 1 (their first/oldest Kid) Hence Total number of kids = (T+2 / J) + 1 cheers Senior Manager Joined: 21 Jul 2009 Posts: 367 Schools: LBS, INSEAD, IMD, ISB - Anything with just 1 yr program. Followers: 14 Kudos [?]: 96 [0], given: 22 Re: Mr. and Mrs Wiley, VIC [#permalink] 06 Feb 2010, 15:05 Their oldest kid is T y/o. From the question stem, their youngest kid alive is J-2 y/o. We need to know how many kids are there between T and J-2 spaced exactly J years apart. This is an arithmetic progression. (J-2) + (n-1)J = T, inclusive. This gives n = (T+2)/J. Question stem also states that they are going to have a baby after 2 yrs from now, so we have to add that kid to n to get the total number of kids the Wiley family will have. Therefore, answer is A. _________________ I am AWESOME and it's gonna be LEGENDARY!!! Intern Joined: 17 Nov 2009 Posts: 37 Schools: University of Toronto, Mcgill, Queens Followers: 0 Kudos [?]: 28 [0], given: 9 Re: Mr. and Mrs Wiley, VIC [#permalink] 13 Feb 2010, 00:21 BarneyStinson wrote: Their oldest kid is T y/o. From the question stem, their youngest kid alive is J-2 y/o. We need to know how many kids are there between T and J-2 spaced exactly J years apart. This is an arithmetic progression. (J-2) + (n-1)J = T, inclusive. This gives n = (T+2)/J. Question stem also states that they are going to have a baby after 2 yrs from now, so we have to add that kid to n to get the total number of kids the Wiley family will have. Therefore, answer is A. Hi Barney, Your solution makes sense as its simple AP you applied, but I failed to comprehend that how you get J-2 as first element. As Q says that they'll have kids after every J years and their oldest kid is T years old and the next kid will be due after two years from now but we don't know that how many years back first kid was born....may be I didn't get rightly. Can you please explain. Thanks. Cheers! _________________ --Action is the foundational key to all success. CEO Status: Nothing comes easy: neither do I want. Joined: 12 Oct 2009 Posts: 2793 Location: Malaysia Concentration: Technology, Entrepreneurship Schools: ISB '15 (M) GMAT 1: 670 Q49 V31 GMAT 2: 710 Q50 V35 Followers: 175 Kudos [?]: 892 [0], given: 235 Re: Mr. and Mrs Wiley, VIC [#permalink] 13 Feb 2010, 01:03 Ans A their first child was born after J years... thus 1 child ---> j years => thus after another J years his age = J thus his age is J --> after 2J years and 2j after 3j years his present age is T which is after T years. thus total time after 2years will be T+2 since after every J year they have a child after T+2 they will have \frac{(T+2)}{J} + 1 ( +1 is for the oldest) thus A _________________ Fight for your dreams :For all those who fear from Verbal- lets give it a fight Money Saved is the Money Earned Jo Bole So Nihaal , Sat Shri Akaal Support GMAT Club by putting a GMAT Club badge on your blog/Facebook Get the best GMAT Prep Resources with GMAT Club Premium Membership Gmat test review : 670-to-710-a-long-journey-without-destination-still-happy-141642.html Intern Joined: 06 Apr 2012 Posts: 28 Followers: 0 Kudos [?]: 4 [0], given: 37 Re: Mr. and Mrs Wiley, VIC [#permalink] 21 Nov 2012, 07:46 jeeteshsingh wrote: Need the solution using Algebra.... Mr. & Mrs Wiley have a child every J years. Their oldest child is now T years old. If they have a child 2 years from now, how many children will they have in total? (A) \frac{T+2}{J} + 1 (B) JT + 1 (C) \frac{J}{T} + \frac{1}{T} (D) TJ - 1 (E) \frac{T+J}{J} [Reveal] Spoiler: OA: (A) Source: Manhattan Guide Please give the algebric solution. Bunuel - would really appreciate you providing your bit on solving the original problem above algebraically. The problem and various explanations remain confusing. Should we think of it as a progression or some other way? Please share your take. Thank you. Re: Mr. and Mrs Wiley, VIC [#permalink] 21 Nov 2012, 07:46 Similar topics Replies Last post Similar Topics: 1 Mr. and Mrs. O’Leary (SC) 5 08 Jul 2012, 07:15 Mr. INVESTOR invested a total of$12,000 for a one-year 4 30 Mar 2007, 09:24
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