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Mr. Jones drove from Town A to Town B in x hours. On the

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Mr. Jones drove from Town A to Town B in x hours. On the [#permalink] New post 09 Feb 2004, 11:23
Mr. Jones drove from Town A to Town B in x hours. On the return trip over the same route, his average speed was twice as fast. Which of the following expresses the total number of driving hours for the round trip?

(A) 2x/3
(B) 3x/2
(C) 5x/3
(D) 2x
(E) 3x
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 [#permalink] New post 09 Feb 2004, 11:29
Ans: B = 3x/2

It takes half the time to cross the same distance by travelling
at twice the speed.

Thus, x + x/2 = 3x/2

Last edited by kpadma on 11 Feb 2004, 05:21, edited 1 time in total.
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 [#permalink] New post 09 Feb 2004, 11:33
The Official Answer is D..

Can someone explain.. Or is it a typo.

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 [#permalink] New post 09 Feb 2004, 11:34
I am sorry Kpadma..you are right the answer is B
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 [#permalink] New post 11 Feb 2004, 00:33
Kpadma i will be highly thankfull if u expalin this to me in detail.
Well here is my approach.

Point (A) ----------------------- Point (B)

Going time = X
Let going speed = Y Km/hr.
Distance covered = speed * distance
= XY

Coming speed = 2Y Km/hr.
Let Coming time = T
Distance covered is same as in going = 2Y * T

So , 2Y * T = XY
or T = X/2.

Whats wrong here????????
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 [#permalink] New post 11 Feb 2004, 09:13
instead of such a long procedure .. there's a shortcut..
u know it takes x hours to travel A-B and return in twice as fast so u will cover return journey in half the time u spend while goin.. so x/2 ..add both x+x/2= 3x/2..
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 [#permalink] New post 12 Feb 2004, 04:34
I mis understood the question.
I thought it asked how much time did it take in the return trip.
Poor me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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 [#permalink] New post 28 May 2007, 20:05
shubhangi wrote:
instead of such a long procedure .. there's a shortcut..
u know it takes x hours to travel A-B and return in twice as fast so u will cover return journey in half the time u spend while goin.. so x/2 ..add both x+x/2= 3x/2..


yes. this is the most intuitive way to solve it rather than get boggled down in formulas and pluggin in "smart numbers"

here is the "smart number" way

R*T=D
let t=x
let d= 8 ("smart number")

going from A to B
R*T=D
R*x=8
plug in another smart number for x (x=4)
R*4=8
R=2

on the way back from B to A
R*T=D
R*?=8
4*?=8 (twice as fast)
T=2

therefore, 4+2=6 hours total
we originally set x=4
therefore, 6 = 3/2x
  [#permalink] 28 May 2007, 20:05
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