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Mr. Kramer, the losing candidate in a two-candidate

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 [#permalink] New post 19 Feb 2006, 12:33
N=number of votes
Remaining votes=0.6*N

We look for x such as: x*0.6*N+0.4*N>0.5*N
x*0.6>(0.5-0.4)
x>1/6=16.66%

Answer is D.
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 [#permalink] New post 20 Feb 2006, 02:15
Or...

940.000 votes he received (which we now is 40% of total) translates into 2.350.000 of total votes....

So 50% of the votes would equal to 1.175.000, thus he would need additional 1175-940=235.000 votes

The question asks what percent of the REMAINING votes he would need, so the REMAINING votes equates to 2.350.000-940.000=1.410.000

The answer 235/1410=0.166666667 or 17%
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Re: PERCENTAGE PROB.. [#permalink] New post 18 Nov 2008, 12:15
bindrakaran001 wrote:
Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 40 percent of all the votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast?
(A) 10%
(B) 12%
(C) 15%
(D) 17%
(E) 20%


It is D

Assuming he got 40 of the 100 votes. He needs 10 more==> 10/60X100=16.66
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Re: PERCENTAGE PROB.. [#permalink] New post 18 Nov 2008, 15:00
can this really be done by assuming 100 ? Can you pls confirm the QA bindrakaran ?
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Re: Mr. Kramer's votes [#permalink] New post 11 May 2011, 17:50
you really dont have to use a lot of algebra.

given (40/100)(V) = 942568 where V is the total number of votes

=> (60V/100) is the remaining and we were asked to find what % of remaining votes does he need to win

( he needs 10% more votes to win)

=> \((p/100)(60V/100) = 10V/100\)

=> p = 17%

Answer is D.

if you look carefully we dont even have to use the 942568 any where in our calculation. Hope it helps.




tonebeeze wrote:
I got this problem correct using brute force algebra, but the process took to long. What is the most efficient method to solve problems like this one?


Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 40 percent of all votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast?

a. 10%
b. 12%
c. 15%
d. 17%
e. 20%
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Re: PS: What's a Quick Way to Get This? [#permalink] New post 11 May 2011, 20:22
Good method to solve these kinds of questions.

Equating to 10,1 and 5 respectively.
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Re: PS: What's a Quick Way to Get This? [#permalink] New post 11 May 2011, 21:58
942568 = 0.4x

942568 + y = 0.5x

y = 0.1x

=> 0.1x/0.6x * 100 = 100/6 = 50/3 = 16.66 ~ 17%

Answer - D
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Re: Mr. Kramer, the losing candidate in a two-candidate [#permalink] New post 24 Apr 2014, 23:19
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Re: Mr. Kramer, the losing candidate in a two-candidate [#permalink] New post 17 Nov 2014, 07:03
Let x = total # of votes casted
y= % of additional votes needed
so, 0.4x + y*0.6x = 0.5x

solve for x. Ans
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Re: Mr. Kramer, the losing candidate in a two-candidate [#permalink] New post 27 Dec 2015, 19:11
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: Mr. Kramer, the losing candidate in a two-candidate   [#permalink] 27 Dec 2015, 19:11

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Mr. Kramer, the losing candidate in a two-candidate

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