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# Mr. Kramer, the losing candidate in a two-candidate

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Intern
Joined: 16 Aug 2005
Posts: 37
Followers: 0

Kudos [?]: 2 [0], given: 0

We look for x such as: x*0.6*N+0.4*N>0.5*N
x*0.6>(0.5-0.4)
x>1/6=16.66%

Director
Joined: 05 Feb 2006
Posts: 898
Followers: 1

Kudos [?]: 69 [0], given: 0

Or...

940.000 votes he received (which we now is 40% of total) translates into 2.350.000 of total votes....

The question asks what percent of the REMAINING votes he would need, so the REMAINING votes equates to 2.350.000-940.000=1.410.000

Manager
Joined: 23 Jul 2008
Posts: 203
Followers: 1

Kudos [?]: 62 [0], given: 0

Re: PERCENTAGE PROB.. [#permalink]  18 Nov 2008, 12:15
bindrakaran001 wrote:
Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 40 percent of all the votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast?
(A) 10%
(B) 12%
(C) 15%
(D) 17%
(E) 20%

It is D

Assuming he got 40 of the 100 votes. He needs 10 more==> 10/60X100=16.66
Manager
Joined: 14 Oct 2008
Posts: 160
Followers: 1

Kudos [?]: 39 [0], given: 0

Re: PERCENTAGE PROB.. [#permalink]  18 Nov 2008, 15:00
can this really be done by assuming 100 ? Can you pls confirm the QA bindrakaran ?
Director
Joined: 01 Feb 2011
Posts: 758
Followers: 14

Kudos [?]: 85 [0], given: 42

you really dont have to use a lot of algebra.

given (40/100)(V) = 942568 where V is the total number of votes

=> (60V/100) is the remaining and we were asked to find what % of remaining votes does he need to win

( he needs 10% more votes to win)

=> $$(p/100)(60V/100) = 10V/100$$

=> p = 17%

if you look carefully we dont even have to use the 942568 any where in our calculation. Hope it helps.

tonebeeze wrote:
I got this problem correct using brute force algebra, but the process took to long. What is the most efficient method to solve problems like this one?

Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 40 percent of all votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast?

a. 10%
b. 12%
c. 15%
d. 17%
e. 20%
VP
Status: There is always something new !!
Affiliations: PMI,QAI Global,eXampleCG
Joined: 08 May 2009
Posts: 1354
Followers: 15

Kudos [?]: 191 [0], given: 10

Re: PS: What's a Quick Way to Get This? [#permalink]  11 May 2011, 20:22
Good method to solve these kinds of questions.

Equating to 10,1 and 5 respectively.
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SVP
Joined: 16 Nov 2010
Posts: 1675
Location: United States (IN)
Concentration: Strategy, Technology
Followers: 32

Kudos [?]: 412 [0], given: 36

Re: PS: What's a Quick Way to Get This? [#permalink]  11 May 2011, 21:58
942568 = 0.4x

942568 + y = 0.5x

y = 0.1x

=> 0.1x/0.6x * 100 = 100/6 = 50/3 = 16.66 ~ 17%

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GMAT Club Legend
Joined: 09 Sep 2013
Posts: 8152
Followers: 416

Kudos [?]: 110 [0], given: 0

Re: Mr. Kramer, the losing candidate in a two-candidate [#permalink]  24 Apr 2014, 23:19
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Intern
Joined: 05 Feb 2014
Posts: 26
Followers: 0

Kudos [?]: 2 [0], given: 65

Re: Mr. Kramer, the losing candidate in a two-candidate [#permalink]  17 Nov 2014, 07:03
Let x = total # of votes casted
so, 0.4x + y*0.6x = 0.5x

solve for x. Ans
GMAT Club Legend
Joined: 09 Sep 2013
Posts: 8152
Followers: 416

Kudos [?]: 110 [0], given: 0

Re: Mr. Kramer, the losing candidate in a two-candidate [#permalink]  27 Dec 2015, 19:11
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
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Re: Mr. Kramer, the losing candidate in a two-candidate   [#permalink] 27 Dec 2015, 19:11

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