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n and k are positive integers. If n=(22)(3)(53)/15k, is n<k?

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n and k are positive integers. If n=(22)(3)(53)/15k, is n<k? [#permalink]

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New post 09 Jun 2016, 22:45
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n and k are positive integers. If n=(2^2)(3)(5^3)/15k, is n<k?
1) n<10
2) k>4

*An answer will be posted in 2 days.
[Reveal] Spoiler: OA

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Last edited by MathRevolution on 13 Jun 2016, 01:09, edited 1 time in total.
Expert Post
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n and k are positive integers. If n=(22)(3)(53)/15k, is n<k? [#permalink]

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New post 13 Jun 2016, 01:08
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If we modify the original condition and the question, we get n=100/k, k=100/n. If we substitute this into n<k?, the question becomes n<100/n?, n^2<100=10^2?, n<10?. Hence, the correct answer is A.

- Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.
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Re: n and k are positive integers. If n=(22)(3)(53)/15k, is n[#permalink]

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New post 13 Jun 2016, 05:45
MathRevolution wrote:
n and k are positive integers. If n=(2^2)(3)(5^3)/15k, is n<k?
1) n<10
2) k>4

*An answer will be posted in 2 days.

Both sufficient


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Re: n and k are positive integers. If n=(22)(3)(53)/15k, is n [#permalink] 13 Jun 2016, 05:45
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n and k are positive integers. If n=(22)(3)(53)/15k, is n<k?

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