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See, t0 is odd. Then we add an odd number (n=1), so t1 is even. Then we add an even number(n=2), so t2 is even. Then we add an odd number (n=3), so t3 is odd. Then we add an even number(n=4), so t4 is odd. Then we add an odd number(n=5), so t5 is even. Then we add an even number(n=6), so t6 is even. Then we add an odd number(n=7), so t7 is odd. Then we add an even number(n=8), so t8 is odd. Etc........

As you could see here the sequence is connected with divisibility by 4. So (1) tells us about divisibility by 3 and it should be not sufficient. See countrexample: t2 is even (n+1 is 3), t8 is odd (n+1=9) (2) alone should be sufficient since it tells us about the divisibility by 4, and we see that n which are divided by 4 with remainder of 1 or 2 is even. If the remainder is 0 or 3, it is odd. Here the reminder is 1 (n-1 is divided by 4), so the term should be even.

The answer is (B) _________________

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Re: n is an integer greater than or equal to 0. The sequence tn [#permalink]
05 Oct 2013, 09:13

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Re: n is an integer greater than or equal to 0. The sequence tn [#permalink]
24 Nov 2013, 14:22

It should be E...n-1 being divisible by 4, based on the chart, that means it's either 4 (as you can see if it's 4, then the next term in the sequence is 6), or 24 for (in which case the next term in the series is 31). OA is incorrect.

Re: n is an integer greater than or equal to 0. The sequence tn [#permalink]
24 Nov 2013, 14:40

2

This post received KUDOS

Expert's post

1

This post was BOOKMARKED

AccipiterQ wrote:

n is an integer greater than or equal to 0. The sequence \(t_n\) for n > 0 is defined as \(t_n = t_{n-1} + n\). Given that \(t_0 = 3\), is tn even?

(1) n + 1 is divisible by 3 (2) n - 1 is divisible by 4

It should be E...n-1 being divisible by 4, based on the chart, that means it's either 4 (as you can see if it's 4, then the next term in the sequence is 6), or 24 for (in which case the next term in the series is 31). OA is incorrect.

The OA is correct.

(2) n - 1 is divisible by 4 means that \(n=4k+1\), thus n is 1, 5, 9, ...

Re: n is an integer greater than or equal to 0. The sequence tn [#permalink]
28 Dec 2013, 08:34

1

This post received KUDOS

First off let's see the sequence behavior charting some numbers.

t(0)=3+0 = O t(1)=3+1 = E t(2)=4+2 = E t(3)=6+3 = O t(4)=9+4 = O t(5)=13+5= E t(8) = O

we can notice a repeating pattern (E, E, O, O) we need to figure out how n relates to a multiple of 4.

st1 n could be 2, 5, 8, 11, 14 etc.. checking the chart we can tell that this statement is not sufficient st2 tells us how n relates to a multiple of 4 and indeed if we plug some values in we can safely claim that t(n) is even. _________________

learn the rules of the game, then play better than anyone else.

Re: n is an integer greater than or equal to 0. The sequence tn [#permalink]
05 Jan 2014, 07:26

I have a doubt here, 2nd part says that it is divisible by 4 then why have you wrote the expression as n= 4k+1. it doesn't talks about remainder here right? isn't n=4k enough?

Bunuel wrote:

AccipiterQ wrote:

n is an integer greater than or equal to 0. The sequence \(t_n\) for n > 0 is defined as \(t_n = t_{n-1} + n\). Given that \(t_0 = 3\), is tn even?

(1) n + 1 is divisible by 3 (2) n - 1 is divisible by 4

It should be E...n-1 being divisible by 4, based on the chart, that means it's either 4 (as you can see if it's 4, then the next term in the sequence is 6), or 24 for (in which case the next term in the series is 31). OA is incorrect.

The OA is correct.

(2) n - 1 is divisible by 4 means that \(n=4k+1\), thus n is 1, 5, 9, ...

Re: n is an integer greater than or equal to 0. The sequence tn [#permalink]
05 Jan 2014, 08:57

Expert's post

rgyanani wrote:

I have a doubt here, 2nd part says that it is divisible by 4 then why have you wrote the expression as n= 4k+1. it doesn't talks about remainder here right? isn't n=4k enough?

Bunuel wrote:

AccipiterQ wrote:

n is an integer greater than or equal to 0. The sequence \(t_n\) for n > 0 is defined as \(t_n = t_{n-1} + n\). Given that \(t_0 = 3\), is tn even?

(1) n + 1 is divisible by 3 (2) n - 1 is divisible by 4

It should be E...n-1 being divisible by 4, based on the chart, that means it's either 4 (as you can see if it's 4, then the next term in the sequence is 6), or 24 for (in which case the next term in the series is 31). OA is incorrect.

The OA is correct.

(2) n - 1 is divisible by 4 means that \(n=4k+1\), thus n is 1, 5, 9, ...

Re: n is an integer greater than or equal to 0. The sequence tn [#permalink]
07 Jan 2014, 01:14

Hi Bunuel pl review the logic below

its a AP where d = tn-tn-1= n where 3 is the first term

Now the tn = 3+ (n-1)n {by formula tn= a+(n-1)d}

in this equation n and n-1 are consecutive numbers

for statement #1: n+1, which is next consecutive number in the sequence, is divisible by 3, but we don't know whether its even or odd ( including 3,6,9,..) so insuff

for statement #2: n-1 is divisible by 4 so n-1 is even hence n is odd and n(n-1) is even. And 3 + even = odd suff

T_n can only be even if the sum of integers from 1 to n is odd, as odd (3)+ odd=even

1. n+1 can only be divisible by 3 if T_n= T_2, T_5, T_8, T_11.... sum of integers from 1 to 2=3 (odd) sum of integers from 1 to 5=15 (odd) sum of integers from 1 to 8=36 (even)

Not sufficient

2. n-1 can only be divisible by 4 if T_n= T_5, T_9, T_13, T_17..... sum of integers from 1 to 5=15 (odd) sum of integers from 1 to 9=45 (odd) sum of integers from 1 to 13= 91 (odd) sum of integers from 1 to 17=153 (odd)

Re: n is an integer greater than or equal to 0. The sequence tn [#permalink]
07 Jul 2014, 07:55

gmat6nplus1 wrote:

First off let's see the sequence behavior charting some numbers.

t(0)=3+0 = O t(1)=3+1 = E t(2)=4+2 = E t(3)=6+3 = O t(4)=9+4 = O t(5)=13+5= E t(8) = O

we can notice a repeating pattern (E, E, O, O) we need to figure out how n relates to a multiple of 4.

st1 n could be 2, 5, 8, 11, 14 etc.. checking the chart we can tell that this statement is not sufficient st2 tells us how n relates to a multiple of 4 and indeed if we plug some values in we can safely claim that t(n) is even.

how exactly does st.1 tell us n could be 2, 5, 8 ,11 ,14 could you show the plugging in?

Re: n is an integer greater than or equal to 0. The sequence tn [#permalink]
25 Jan 2015, 04:22

sagnik2422 wrote:

gmat6nplus1 wrote:

First off let's see the sequence behavior charting some numbers.

t(0)=3+0 = O t(1)=3+1 = E t(2)=4+2 = E t(3)=6+3 = O t(4)=9+4 = O t(5)=13+5= E t(8) = O

we can notice a repeating pattern (E, E, O, O) we need to figure out how n relates to a multiple of 4.

st1 n could be 2, 5, 8, 11, 14 etc.. checking the chart we can tell that this statement is not sufficient st2 tells us how n relates to a multiple of 4 and indeed if we plug some values in we can safely claim that t(n) is even.

how exactly does st.1 tell us n could be 2, 5, 8 ,11 ,14 could you show the plugging in?

Statement says 3k=n+1 so n =3k-1, putting k=1 we get n=2, k=2 gives n=5 , k=3 gives n=8 and so on...... _________________

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Re: n is an integer greater than or equal to 0. The sequence tn
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25 Jan 2015, 04:22

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