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# n = k^2, where k is a positive integer. What is n? 1) k is

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Manager
Joined: 04 Nov 2006
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n = k^2, where k is a positive integer. What is n? 1) k is [#permalink]  09 Dec 2006, 18:12
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n = k^2, where k is a positive integer. What is n?

1) k is an odd prime
2) n has exactly 4 positive factors
Senior Manager
Joined: 23 May 2005
Posts: 266
Location: Sing/ HK
Followers: 1

Kudos [?]: 19 [0], given: 0

[#permalink]  09 Dec 2006, 20:13
This question is strange... it contradicts itself. Your stem states that n is perfect square. However, (2) tells you that n has exactly 4 positive factors. Any perfect square will have an odd number of factors. So (2) contradicts the stem

(1) INSUFF. k could be 3, 5, 7...
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Impossible is nothing

Manager
Joined: 04 Nov 2006
Posts: 158
Followers: 3

Kudos [?]: 8 [0], given: 0

[#permalink]  09 Dec 2006, 20:46
Yeah, I came to the same conclusion. In the practice test, the explanation to this problem states: "All odd square primes have exactly 4 factors..."

Seems to be an error in the question.
[#permalink] 09 Dec 2006, 20:46
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# n = k^2, where k is a positive integer. What is n? 1) k is

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