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n(Senior) = 15 and n(Senior & Chemistry) =20 , Total no

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n(Senior) = 15 and n(Senior & Chemistry) =20 , Total no [#permalink] New post 18 Feb 2004, 23:51
n(Senior) = 15 and n(Senior & Chemistry) =20 , Total no of students is 40. The no of students who are not senior is what percentage of the number of students who major in chemistry ?
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 [#permalink] New post 19 Feb 2004, 04:53
is it 20%. Will explain if the answer is rite.
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 [#permalink] New post 19 Feb 2004, 05:33
n(Senior) = 15 and n(Senior & Chemistry) =20

The can't be possible n(S & C) =< n(S).
Could you check the question?
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 [#permalink] New post 19 Feb 2004, 11:01
i know.. it seems wrong to me.. first.. but answer is 20 as rakesh.. said
how did u work out rakesh.. pls..explain step wise
thanks.
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 [#permalink] New post 19 Feb 2004, 16:30
Subhangi, yes the question is wrong. But anyways n(S)=15 , so I assumed only seniors as 15, then we will get both (senior and chem) as 20 and only chem as 5. So those who are not senior =5 and those who are not senior=25. So 5 is 20% of 25. I worked out by drawing venn diagram.
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 [#permalink] New post 19 Feb 2004, 17:35
So those who are not senior =5 and those who are not senior=25.
what does this mean..??
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 [#permalink] New post 19 Feb 2004, 18:03
:oops those who r not senior (only chem)=5 and those who major in chem = 20+5=25
  [#permalink] 19 Feb 2004, 18:03
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n(Senior) = 15 and n(Senior & Chemistry) =20 , Total no

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