Quote:
(n-x) + (n-y) + (n-c) + (n-k)
What is the value of the expression above?
(1) The average (arithmetic mean) of x, y, c, and k is n.
(2) x, y, c, and k are consecutive integers.
laythesmack23 wrote:
Angela780 wrote:
Can someone explain this?
Can you explain this problem for me, I'm not understanding it.
It asks for the value of (n-x) + (n-y) + (n-c) + (n-k) .......or 4n-(x+y+c+k) .....so that means we need to know the value of n
& x+y+c+k .....
statement:: 1 says ..... The average (arithmetic mean) of x, y, c, and k is n..... that means ....
\frac{x+y+c+k}{4}= n ... Theforefore, 4n = x+y+c+k ...
when plugging in the value in the expression given .... 4n-4n .. Therefore, 0.
The value of above expression is 0. Sufficient.
Statement :: 2 says x, y, c, and k are consecutive integers. ..lets say for ex. the consecutive integers x,y,c,k are 1,2,3,4, respectively...
therefore, we have (n-1)(n-2)(n-3)(n-4)..... or 4n-10 .. so here we need to know the value of n in order to know the value of the
expression above........ so, Insufficient.
Hence, A ............
Hope it Helps !! & let me know if there is any problem ..............
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