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# Need help to solve this.

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Manager
Joined: 19 Sep 2010
Posts: 56
Location: Pune, India
Followers: 13

Kudos [?]: 27 [0], given: 9

Need help to solve this. [#permalink]

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14 Dec 2010, 06:39
Hi,

I'm not getting to solve this. 10^-5 - 10^-12 ??

I did this way;

lets assume 10^-5 =a
then, a-a^2/100. not getting the value of a. how else can we solve this?
Manager
Joined: 03 Jun 2009
Posts: 50
Followers: 1

Kudos [?]: 12 [0], given: 7

Re: Need help to solve this. [#permalink]

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14 Dec 2010, 07:23
SoniaSaini wrote:
Hi,

I'm not getting to solve this. 10^-5 - 10^-12 ??

I did this way;

lets assume 10^-5 =a
then, a-a^2/100. not getting the value of a. how else can we solve this?

one more way is...(10^-5 - 10^-12 )
Multiply and divide by 10^12
=> [10^12 (10^-5 - 10^-12 )]/10^12

=> (10^7 - 1) / 10^12
Math Expert
Joined: 02 Sep 2009
Posts: 36625
Followers: 7103

Kudos [?]: 93607 [0], given: 10583

Re: Need help to solve this. [#permalink]

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14 Dec 2010, 07:30
SoniaSaini wrote:
Hi,

I'm not getting to solve this. 10^-5 - 10^-12 ??

I did this way;

lets assume 10^-5 =a
then, a-a^2/100. not getting the value of a. how else can we solve this?

For example like this:
$$10^{-5}-10^{-12}=\frac{1}{10^{5}}-\frac{1}{10^{12}}=\frac{10^7-1}{10^{12}}=\frac{10,000,000-1}{10^{12}}=\frac{9,999,999}{10^{12}}=\frac{9,999,999}{1,000,000,000,000}$$

$$\frac{9,999,999}{1,000,000,000,000}$$ can also be written as $$9.999999*10^{-6}$$ or as $$0.000009999999$$.

Hope it's clear.
_________________
Manager
Joined: 19 Sep 2010
Posts: 56
Location: Pune, India
Followers: 13

Kudos [?]: 27 [0], given: 9

Re: Need help to solve this. [#permalink]

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14 Dec 2010, 08:16
It helped me.
Re: Need help to solve this.   [#permalink] 14 Dec 2010, 08:16
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