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Manager
Joined: 04 Oct 2005
Posts: 246
Followers: 1

Kudos [?]: 22 [0], given: 0

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(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
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Manager
Joined: 28 Jun 2005
Posts: 217
Followers: 1

Kudos [?]: 3 [0], given: 0

I am getting D

using pyth theorm
QR=2RS
St1: The upper triangle would become 30-30-120 Suff to prove
St2: Same as St1; Suff
SVP
Joined: 24 Sep 2005
Posts: 1891
Followers: 12

Kudos [?]: 159 [0], given: 0

(1) for triangle PQR, we have: PRS= PQR+QPR= PQR+30 ---> PRS- PQR=30---> suff
(2) in triangle QPR, we have PQR+ QRP+ QPR= 180 ---> QPR= 30 ----> the same to (1) ---> suff
SVP
Joined: 28 May 2005
Posts: 1740
Location: Dhaka
Followers: 6

Kudos [?]: 75 [0], given: 0

I got D

because it is a right angle triangle

we can write it as Qps + pqs = prs + spr

now qps = qpr+spr

so we can re-write it as qpr + prs + pqs = prs +spr

or , prs - pqs = qpr

now from statement 1 we get the value of qpr = 30 degree.

so we can solve the problem

from statement 2 we get pqr + prq = 150.
PQR+ QRP+ QPR= 180

therefore qpr = 30. so it is sufficient.

_________________

hey ya......

Intern
Joined: 01 Jun 2005
Posts: 40
Followers: 0

Kudos [?]: 0 [0], given: 0

D it is .

Sum of angles = 180. QSP = RSP = 90

therefore, if we cut any angle other than the right angle => the loss in one angle = the gain in the other.

Here the loss is = QPR

Stmt 1. QPR is given -- Suff!
Stmt 2. QPR can be derived -- SUff!
Manager
Joined: 04 Oct 2005
Posts: 246
Followers: 1

Kudos [?]: 22 [0], given: 0

Indeed OA is D, no OE given

Source: Gmatprep
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