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Need your input on this one [#permalink] New post 10 Nov 2005, 06:13
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 [#permalink] New post 10 Nov 2005, 07:00
I am getting D

using pyth theorm
QR=2RS
St1: The upper triangle would become 30-30-120 Suff to prove
St2: Same as St1; Suff
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 [#permalink] New post 10 Nov 2005, 08:14
(1) for triangle PQR, we have: PRS= PQR+QPR= PQR+30 ---> PRS- PQR=30---> suff
(2) in triangle QPR, we have PQR+ QRP+ QPR= 180 ---> QPR= 30 ----> the same to (1) ---> suff
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 [#permalink] New post 10 Nov 2005, 09:07
I got D

because it is a right angle triangle

we can write it as Qps + pqs = prs + spr

now qps = qpr+spr

so we can re-write it as qpr + prs + pqs = prs +spr

or , prs - pqs = qpr

now from statement 1 we get the value of qpr = 30 degree.

so we can solve the problem

from statement 2 we get pqr + prq = 150.
PQR+ QRP+ QPR= 180

therefore qpr = 30. so it is sufficient.

answer should be D
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 [#permalink] New post 10 Nov 2005, 09:16
D it is .

Sum of angles = 180. QSP = RSP = 90

therefore, if we cut any angle other than the right angle => the loss in one angle = the gain in the other.

Here the loss is = QPR

Stmt 1. QPR is given -- Suff!
Stmt 2. QPR can be derived -- SUff!
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 [#permalink] New post 10 Nov 2005, 09:38
Very good ladies and gents,

Indeed OA is D, no OE given

Source: Gmatprep
  [#permalink] 10 Nov 2005, 09:38
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