|
Author |
Message |
|
SVP
Joined: 03 Feb 2003
Posts: 1683
Followers: 4
Kudos [?]:
16
[0], given: 0
|
new formal logic quiz [#permalink]
31 Aug 2003, 05:11
Premises:
(1) A is necessary for B
(2) B, unless C
(3) A is sufficient for D
Which of the following is the correct conclusion?
(1) D, unless A
(2) A, unless D
(3) C, unless D
(4) D, unless C
(5) none of the above
|
|
|
|
|
|
|
Manager
Joined: 14 Aug 2003
Posts: 90
Location: barcelona
Followers: 1
Kudos [?]:
0
[0], given: 0
|
mmmm...
id say (1) and (2) say the same and so do (3) and (4)... and id say that (1) is wrong and (3) can be true, but can be not true, so i vote for (5)
|
|
|
|
|
|
SVP
Joined: 03 Feb 2003
Posts: 1683
Followers: 4
Kudos [?]:
16
[0], given: 0
|
Alas, (5) is wrong. I do not see a clear rationale, only telling fortunes by coffee ground. A hint—all the premises have to be transformed into an if/then form.
Last edited by stolyar on 31 Aug 2003, 08:04, edited 1 time in total.
|
|
|
|
|
|
Manager
Joined: 14 Aug 2003
Posts: 90
Location: barcelona
Followers: 1
Kudos [?]:
0
[0], given: 0
|
alas, alas! that is exactly what i tried... let me think:
(P1) A is necessary for B
this means "if not A, then not B"... i visualize this as B<A, where "<" means "contained in"
(P2) B, unless C
this means "if not C, then B"... which equals "if not B, then C"... i visualize this as B and C intersecting each other
(P3) A is sufficient for D
this means "if A then D"... i visualize this as A<D
now...
(Q1) D unless A... this means A can be true while D is false... which is in contradiction with P1
(Q3) C unless D... we can have C true, D false; C true, D true; C true, D false, but not C false and D false... lets see... if not C (C false), by P2, then B... if B, by P1, then A... if A, by P3, then D...
i would now vote for (3) AND (4)... (they are equivalent, arent they?)
|
|
|
|
|
|
SVP
Joined: 03 Feb 2003
Posts: 1683
Followers: 4
Kudos [?]:
16
[0], given: 0
|
Another hint: transform all the premises in a clear and comfortable form, and unite them:
(1) A is necessary for B== If B, then A
(2) B, unless C ======= If not C, then B
(3) A is sufficient for D == If A, then D
So, we see the chain: (2)—(1)—(3): If not C, then B. If B, then A. If A, then D.
Then, formulate the right conclusion in 2 steps.
|
|
|
|
|
|
Manager
Joined: 14 Aug 2003
Posts: 90
Location: barcelona
Followers: 1
Kudos [?]:
0
[0], given: 0
|
aargh! im feeling so stupid!
we have B=>A, notC=>B, A=>D... or notC=>B=>A=>D
D unless A? notD=>A false (in fact, notD=>notA)
A unless D? notA=>D false
C unless D? notC=>D... winner!!!!
D unless C? notD=>C... id say this is equivalent to notC=>D... so winner as well, isnt it???
i dont get it stolyar, sorry... so ashamed... i still think answer is (3) AND (4)
|
|
|
|
|
|
SVP
Joined: 03 Feb 2003
Posts: 1683
Followers: 4
Kudos [?]:
16
[0], given: 0
|
If not C, then B. If B, then A. If A, then D.
Step 1: If not C, then D. This equals to...
Step 2: D, unless C.
However, we can transform Step 1: If not D, then C; or C, unless D.
(3) and (4) are the correct answers.
New FLQs coming soon.
|
|
|
|
|
|
Manager
Joined: 14 Aug 2003
Posts: 90
Location: barcelona
Followers: 1
Kudos [?]:
0
[0], given: 0
|
great question, thx!
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Moderators:
metallicafan, rajeevrks27, Zarrolou, souvik101990, PTK, MacFauz, noboru, kissthegmat, carcass, willigetmylifeback, mikemcgarry, doe007, Vercules, Legendaddy, tuanquang269, RaviChandra, Marcab
|