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# New Set of Mixed Questions!!!

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New Set of Mixed Questions!!! [#permalink]  01 Apr 2013, 06:48
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The next set of medium/hard PS questions. I'll post OA's with detailed explanations on Friday. Please, post your solutions along with the answers.

1. The distance from the Y-axis to point K is 1/3 of the distance from the X-axis to point K. If the coordinates of K are (-3, y), what is the distance between point K and X-axis?

A. 1/2
B. 1
C. 3
D. 4.5
E. 9.

Solution: new-set-of-mixed-questions-150204-100.html#p1208436

2. What is the area of a region enclosed by |x/3|+|y/9|=10?

A. 675
B. 1350
C. 2700
D. 5400
E. 10800

Solution: new-set-of-mixed-questions-150204-100.html#p1208441

3. Three workers, A, B, and C, can complete a certain task in 10, 5 and x hours respectively. A starts working alone and 2 hours later B joins. After another 2 hours joins C. After that A, B, and C together complete the task in 15 minutes. What is the value of x?

A. 1
B. 1.25
C. 2
D. 2.5
E. 4

Solution: new-set-of-mixed-questions-150204-100.html#p1208445

4. A draining pipe can empty a pool in 4 hours. On a rainy day, when the pool is full, the draining pipe is opened and the pool is emptied in 6 hours. If rain inflow into the pool is 3 liters per hour, what is the capacity of the pool?

A. 9 liters
B. 18 liters
C. 27 liters
D. 36 liters
E. 45 iters

Solution: new-set-of-mixed-questions-150204-100.html#p1208449

5. For a certain set of numbers, if x is in the set, then both -x^2 and -x^3 are also in the set. If the number 1/2 is in the set , which of the following must also be in the set ?

I. -1/64
II. 1/64
III. 1/2^(1/3)

A. I only,
B. II only,
C. III only,
D. I and II only
E. I, II and III

Solution: new-set-of-mixed-questions-150204-100.html#p1208454

6. A team contributes total of $399 from its members. If each member contributed at least$10, and no one contributed $19, what is the greatest number of members the club could have? A. 37 B. 38 C. 39 D. 40 E. 41 Solution: new-set-of-mixed-questions-150204-100.html#p1208457 7. Mary spent 64 percent of her salary on food (including meat) and 16% of her salary on meat. What percent of the salary spent on food were not spent on meat? A. 16% B. 25% C. 32% D. 48% E. 75% Solution: new-set-of-mixed-questions-150204-100.html#p1208459 8. Usually Holly leaves home to school at 9:00, however today she left home 20 minutes later. In order to be at school on time she increased her usual speed by 20% and still was at school 15 minutes later than usual. What is her usual time from home to school? A. 15 minutes B. 20 minutes C. 25 minutes D. 30 minutes E. 210 minutes Solution: new-set-of-mixed-questions-150204-100.html#p1208462 9. If x and y are integers and x + y = -12, which of the following must be true? A. Both x and y are negative B. xy > 0 C. If y < 0, then x > 0 D. If y > 0, then x < 0 E. x - y > 0 Solution: new-set-of-mixed-questions-150204-100.html#p1208466 10. If n is a non-negative integer and the remainder when 3^n is divided by 4 is a multiple of 3, then which of the following must be true? I. n^2 divided by 4 yields the reminder of 1 II. (-2)^n is less than 0 III. n is a prime number A. I only B. II only C. III only D. I and II only E. II and III only Solution: new-set-of-mixed-questions-150204-100.html#p1208471 BONUS QUESTION: 11. Certain bowl contains 5 red marbles and 3 blue marbles only. One by one, every marble is drawn at random and without replacement. What is the probability that the seventh marble drawn is NOT blue? A. 7/8 B. 3/4 C. 2/3 D. 5/8 E. 3/8 Solution: new-set-of-mixed-questions-150204-100.html#p1208473 Kudos points for each correct solution!!! _________________  Kaplan Promo Code Knewton GMAT Discount Codes Manhattan GMAT Discount Codes Manager Joined: 05 Nov 2012 Posts: 72 Concentration: International Business, Operations Schools: Foster '15 (S) GPA: 3.65 Followers: 1 Kudos [?]: 26 [0], given: 8 Re: New Set of Mixed Questions!!! [#permalink] 19 Apr 2013, 20:29 Bunuel wrote: 7. Mary spent 64 percent of her salary on food (including meat) and 16% of her salary on meat. What percent of the salary spent on food were not spent on meat? A. 16% B. 25% C. 32% D. 48% E. 75% 64% of her salary on food; 16% of her salary on meat; 64%-16%=48% on food but not on meat --> 48/64=3/4=75% of the salary spent on food were not spent on meat. Answer: E. Here is another way to go after this one. Since Mary spent 16% of her salary on meat which means she spent 1/4 of the 64% of her salary on meat and the rest, 3/4 not on meat. So 75%. _________________ ___________________________________________ Consider +1 Kudos if my post helped Math Expert Joined: 02 Sep 2009 Posts: 15064 Followers: 2517 Kudos [?]: 15447 [0], given: 1551 Re: New Set of Mixed Questions!!! [#permalink] 20 Apr 2013, 04:15 Expert's post pikachu wrote: Bunuel wrote: 2. What is the area of a region enclosed by |x/3|+|y/9|=10? A. 675 B. 1350 C. 2700 D. 5400 E. 10800 Find the x and y intercepts. When y=0, then x=30 or x=-30. When x=0, then y=90 or x=-90. So, we have 4 points: (30, 0), (-30, 0) (0, 90), (0, -90). When joining these points we get the rhombus: Attachment: 2.png The area of a rhombus is \frac{d_1*d_2}{2} (where d_1 and d_2 are the lengths of the diagonals), thus the area of the enclosed figure is 60*180/2=5,400. Answer: D. Bunuel what about the following points that also meets the given conditions of |x/3| + | y/9| = 10 but come with a different area. (x,y) = (-3,81) (x,y) = (-3,-81) (x,y) = (3,-81) (x,y) = (3,81) In this case Area of the rectangle will be = 972 or you can have (x,y) = (6,72) (x,y) = (6,-72) (x,y) = (-6,-72) (x,y) = (-6,72) In this case the area of the rectangle will be = 1728. Can you please clarify Below is the graph of |x/3|+|y/9|=10: The points you mention are on it and not making some other figure. _________________ Moderator Status: My Thread Master Bschool Threads-->Krannert(Purdue),WP Carey(Arizona),Foster(Uwashngton) Affiliations: Trained Stage Actor,First aider,Swimmer,Sketch artist,Writer Joined: 27 Jun 2011 Posts: 882 Concentration: Finance, General Management GMAT Date: 12-05-2013 GPA: 3.5 WE: Consulting (Human Resources) Followers: 40 Kudos [?]: 116 [0], given: 57 Re: New Set of Mixed Questions!!! [#permalink] 28 Apr 2013, 21:13 Expert's post 11. Certain bowl contains 5 red marbles and 3 blue marbles only. One by one, every marble is drawn at random and without replacement. What is the probability that the seventh marble drawn is NOT blue? A. 7/8 B. 3/4 C. 2/3 D. 5/8 E. 3/8 The problem can be translated to "If 5 red marbles and 3 blue marbles are arranged in a row, what is the probability that the last marble is red?" Total number of arrangements = 8!/[(5!)*(3!)] = 8*7*6/3! = 8*7 Number of arrangements such that last marble is red = Number of arrangements for 4 red marbles and 3 blue marbles = 7!/[(4!)*(3!)] = 786*5/3! = 7*5 Hence, required probability = 7*5/(887) = 5/8 _________________ Math Expert Joined: 02 Sep 2009 Posts: 15064 Followers: 2517 Kudos [?]: 15447 [0], given: 1551 Re: New Set of Mixed Questions!!! [#permalink] 23 May 2013, 12:26 Expert's post SaraLotfy wrote: Bunuel wrote: 5. For a certain set of numbers, if x is in the set, then both -x^2 and -x^3 are also in the set. If the number 1/2 is in the set , which of the following must also be in the set ? I. -1/64 II. 1/64 III. 1/2^(1/3) A. I only, B. II only, C. III only, D. I and II only E. I, II and III Wouldn't -x^2 = +1/4 since the power is even? or should I treat this as -|X|^2? Since 1/2 is in the set, the so must be: -x^2 = -1/4; -x^3 = -1/8. Since -1/4 is in the set, the so must be: -x^3 = 1/64; Since -1/8 is in the set, the so must be: -x^2 = -1/64. The only number we cannot get is 1/2^(1/3). Answer: D. -x^2=-(\frac{1}{2})^2=-\frac{1}{4} (its -x^2 not (-x)^2). Hope it's clear. _________________ Manager Joined: 30 May 2013 Posts: 93 Location: India Concentration: Entrepreneurship, General Management GPA: 3.82 Followers: 0 Kudos [?]: 13 [0], given: 55 Re: New Set of Mixed Questions!!! [#permalink] 22 Jun 2013, 22:46 g106 wrote: 3. Three workers, A, B, and C, can complete a certain task in 10, 5 and x hours respectively. A starts working alone and 2 hours later B joins. After another 2 hours joins C. After that A, B, and C together complete the task in 15 minutes. What is the value of x? A. 1 B. 1.25 C. 2 D. 2.5 E. 4 A, B, and C, can complete a certain task in 10, 5 and x hours respectively A completes 1/10 of the total work in 1 hr B Completes 1/5 of the total work in 1 hr C completes 1/x of the total work in 1 hr A starts working alone and 2 hours later B joins. After another 2 hours joins C. A completes 2/10 of the total work in 2 hrs later B joins A A&B together can complete 1/10 + 1/5 of the total work in 1 hr = 3/10 A&B work together for 2 hour and they complete 2 * 3/10 = 6/10 of the total work By the time C joins A&B 8/10 of the total work is complete To complete 2/10 of the work A, B & C together take 15 minutes (1/4 hr) 2/10 = ¼( 1/10 + 1/5+ 1/x) 8/10 = 3/10 + 1/X 5/10 = 1/X X = 2 Answer = C Hi, plz help me to find out. i dont understand this point " To complete 2/10 of the work A, B & C together take 15 minutes (1/4 hr) " How come u got 2/10? A and b joins to complete 6/10 of work then c joins. But C'r work rate is 1/X. Then how u got 2/10? Please help me Thanks in adavnce, RRSNATHAN Math Expert Joined: 02 Sep 2009 Posts: 15064 Followers: 2517 Kudos [?]: 15447 [0], given: 1551 Re: New Set of Mixed Questions!!! [#permalink] 23 Jun 2013, 00:39 Expert's post rrsnathan wrote: g106 wrote: 3. Three workers, A, B, and C, can complete a certain task in 10, 5 and x hours respectively. A starts working alone and 2 hours later B joins. After another 2 hours joins C. After that A, B, and C together complete the task in 15 minutes. What is the value of x? A. 1 B. 1.25 C. 2 D. 2.5 E. 4 A, B, and C, can complete a certain task in 10, 5 and x hours respectively A completes 1/10 of the total work in 1 hr B Completes 1/5 of the total work in 1 hr C completes 1/x of the total work in 1 hr A starts working alone and 2 hours later B joins. After another 2 hours joins C. A completes 2/10 of the total work in 2 hrs later B joins A A&B together can complete 1/10 + 1/5 of the total work in 1 hr = 3/10 A&B work together for 2 hour and they complete 2 * 3/10 = 6/10 of the total work By the time C joins A&B 8/10 of the total work is complete To complete 2/10 of the work A, B & C together take 15 minutes (1/4 hr) 2/10 = ¼( 1/10 + 1/5+ 1/x) 8/10 = 3/10 + 1/X 5/10 = 1/X X = 2 Answer = C Hi, plz help me to find out. i dont understand this point " To complete 2/10 of the work A, B & C together take 15 minutes (1/4 hr) " How come u got 2/10? A and b joins to complete 6/10 of work then c joins. But C'r work rate is 1/X. Then how u got 2/10? Please help me Thanks in adavnce, RRSNATHAN Check here: new-set-of-mixed-questions-150204-100.html#p1208445 Hope it helps. Links to OE's are given in the original post. _________________ Math Expert Joined: 02 Sep 2009 Posts: 15064 Followers: 2517 Kudos [?]: 15447 [0], given: 1551 Re: New Set of Mixed Questions!!! [#permalink] 08 Jul 2013, 23:40 Expert's post Bumping for review and further discussion*. Get a kudos point for an alternative solution! *New project from GMAT Club!!! Check HERE _________________ Intern Joined: 05 May 2013 Posts: 27 GMAT 1: 730 Q50 V39 GRE 1: 1480 Q800 V680 Followers: 0 Kudos [?]: 19 [0], given: 4 Re: New Set of Mixed Questions!!! [#permalink] 17 Jul 2013, 03:29 Bunuel wrote: 11. Certain bowl contains 5 red marbles and 3 blue marbles only. One by one, every marble is drawn at random and without replacement. What is the probability that the seventh marble drawn is NOT blue? A. 7/8 B. 3/4 C. 2/3 D. 5/8 E. 3/8 Basically we need to find the probability that the seventh marble drawn is red (so not blue). Now, the initial probability of drawing red marble is 5/8. Without knowing the other results, the probability of drawing red marble will not change for ANY successive draw: second, third, fourth, ..., seventh. Thus the probability that the seventh marble is red is 5/8. The same for blue marble: the probability of drawing blue marble is 3/8, the probability that for instance the 8th marble drawn is blue is still 3/8. There is simply no reason to believe WHY is any draw different from another (provided we don't know the other results). Answer: D. Hi Bunuel, Can you please elaborate your thinking on this qn ? I am having a hard time wrapping my head arnd this. My line of thinking was to calculate the probability that you are left with 1 or two red marbles when you are about to draw the seventh one. Not only was this approach very drawn out, i didnt get this answer. Thanks. Math Expert Joined: 02 Sep 2009 Posts: 15064 Followers: 2517 Kudos [?]: 15447 [0], given: 1551 Re: New Set of Mixed Questions!!! [#permalink] 17 Jul 2013, 05:12 Expert's post vs129 wrote: Bunuel wrote: 11. Certain bowl contains 5 red marbles and 3 blue marbles only. One by one, every marble is drawn at random and without replacement. What is the probability that the seventh marble drawn is NOT blue? A. 7/8 B. 3/4 C. 2/3 D. 5/8 E. 3/8 Basically we need to find the probability that the seventh marble drawn is red (so not blue). Now, the initial probability of drawing red marble is 5/8. Without knowing the other results, the probability of drawing red marble will not change for ANY successive draw: second, third, fourth, ..., seventh. Thus the probability that the seventh marble is red is 5/8. The same for blue marble: the probability of drawing blue marble is 3/8, the probability that for instance the 8th marble drawn is blue is still 3/8. There is simply no reason to believe WHY is any draw different from another (provided we don't know the other results). Answer: D. Hi Bunuel, Can you please elaborate your thinking on this qn ? I am having a hard time wrapping my head arnd this. My line of thinking was to calculate the probability that you are left with 1 or two red marbles when you are about to draw the seventh one. Not only was this approach very drawn out, i didnt get this answer. Thanks. Below discussions might help: a-box-contains-3-yellow-balls-and-5-black-balls-one-by-one-90272.html a-bag-contains-3-white-balls-3-black-balls-2-red-balls-100023.html each-of-four-different-locks-has-a-matching-key-the-keys-101553.html if-40-people-get-the-chance-to-pick-a-card-from-a-canister-97015.html new-set-of-mixed-questions-150204-100.html#p1208473 a-medical-researcher-must-choose-one-of-14-patients-to-127396.html a-bag-contains-3-white-balls-3-black-balls-2-red-balls-100023.html _________________ Intern Joined: 26 Feb 2013 Posts: 3 Followers: 0 Kudos [?]: 0 [0], given: 0 Re: New Set of Mixed Questions!!! [#permalink] 06 Aug 2013, 16:27 the function f is defined for positive three digit integer n by f(n) = 2^x3^y5^z, where x,y,z are the hundreds, tens, and units digits of n, respectively. if m and v are three digit positive integers such that f(m) = 9 f(v), then m - v = note: 2^x denote x is power of 2 anyone please give me solution of this problem Math Expert Joined: 02 Sep 2009 Posts: 15064 Followers: 2517 Kudos [?]: 15447 [0], given: 1551 Re: New Set of Mixed Questions!!! [#permalink] 11 Aug 2013, 09:30 Expert's post Riyad47 wrote: the function f is defined for positive three digit integer n by f(n) = 2^x3^y5^z, where x,y,z are the hundreds, tens, and units digits of n, respectively. if m and v are three digit positive integers such that f(m) = 9 f(v), then m - v = note: 2^x denote x is power of 2 anyone please give me solution of this problem Discussed here: the-function-f-is-defined-for-each-positive-three-digit-100847.html _________________ Senior Manager Joined: 10 Jul 2013 Posts: 348 Followers: 2 Kudos [?]: 68 [0], given: 102 Re: New Set of Mixed Questions!!! [#permalink] 11 Aug 2013, 11:14 Bunuel wrote: The next set of medium/hard PS questions. I'll post OA's with detailed explanations on Friday. Please, post your solutions along with the answers. 1. The distance from the Y-axis to point K is 1/3 of the distance from the X-axis to point K. If the coordinates of K are (-3, y), what is the distance between point K and X-axis? A. 1/2 B. 1 C. 3 D. 4.5 E. 9. Solution: new-set-of-mixed-questions-150204-100.html#p1208436 2. What is the area of a region enclosed by |x/3|+|y/9|=10? A. 675 B. 1350 C. 2700 D. 5400 E. 10800 Solution: new-set-of-mixed-questions-150204-100.html#p1208441 3. Three workers, A, B, and C, can complete a certain task in 10, 5 and x hours respectively. A starts working alone and 2 hours later B joins. After another 2 hours joins C. After that A, B, and C together complete the task in 15 minutes. What is the value of x? A. 1 B. 1.25 C. 2 D. 2.5 E. 4 Solution: new-set-of-mixed-questions-150204-100.html#p1208445 4. A draining pipe can empty a pool in 4 hours. On a rainy day, when the pool is full, the draining pipe is opened and the pool is emptied in 6 hours. If rain inflow into the pool is 3 liters per hour, what is the capacity of the pool? A. 9 liters B. 18 liters C. 27 liters D. 36 liters E. 45 iters Solution: new-set-of-mixed-questions-150204-100.html#p1208449 5. For a certain set of numbers, if x is in the set, then both -x^2 and -x^3 are also in the set. If the number 1/2 is in the set , which of the following must also be in the set ? I. -1/64 II. 1/64 III. 1/2^(1/3) A. I only, B. II only, C. III only, D. I and II only E. I, II and III Solution: new-set-of-mixed-questions-150204-100.html#p1208454 6. A team contributes total of$399 from its members. If each member contributed at least $10, and no one contributed$19, what is the greatest number of members the club could have?

A. 37
B. 38
C. 39
D. 40
E. 41

Solution: new-set-of-mixed-questions-150204-100.html#p1208457

7. Mary spent 64 percent of her salary on food (including meat) and 16% of her salary on meat. What percent of the salary spent on food were not spent on meat?

A. 16%
B. 25%
C. 32%
D. 48%
E. 75%

Solution: new-set-of-mixed-questions-150204-100.html#p1208459

8. Usually Holly leaves home to school at 9:00, however today she left home 20 minutes later. In order to be at school on time she increased her usual speed by 20% and still was at school 15 minutes later than usual. What is her usual time from home to school?

A. 15 minutes
B. 20 minutes
C. 25 minutes
D. 30 minutes
E. 210 minutes

Solution: new-set-of-mixed-questions-150204-100.html#p1208462

9. If x and y are integers and x + y = -12, which of the following must be true?

A. Both x and y are negative
B. xy > 0
C. If y < 0, then x > 0
D. If y > 0, then x < 0
E. x - y > 0

Solution: new-set-of-mixed-questions-150204-100.html#p1208466

10. If n is a non-negative integer and the remainder when 3^n is divided by 4 is a multiple of 3, then which of the following must be true?

I. n^2 divided by 4 yields the reminder of 1
II. (-2)^n is less than 0
III. n is a prime number

A. I only
B. II only
C. III only
D. I and II only
E. II and III only

Solution: new-set-of-mixed-questions-150204-100.html#p1208471

BONUS QUESTION:
11. Certain bowl contains 5 red marbles and 3 blue marbles only. One by one, every marble is drawn at random and without replacement. What is the probability that the seventh marble drawn is NOT blue?

A. 7/8
B. 3/4
C. 2/3
D. 5/8
E. 3/8

Solution: new-set-of-mixed-questions-150204-100.html#p1208473

Kudos points for each correct solution!!!

really a good set of practice...thanks
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Asif vai.....

Manager
Joined: 22 Mar 2013
Posts: 102
Location: India
Concentration: General Management, Strategy
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Kudos [?]: 23 [0], given: 31

Re: New Set of Mixed Questions!!! [#permalink]  02 Sep 2013, 11:44
Bonus question:
11. Certain bowl contains 5 red marbles and 3 blue marbles only. One by one, every marble is drawn at random and without replacement. What is the probability that the seventh marble drawn is NOT blue?

A. 7/8
B. 3/4
C. 2/3
D. 5/8
E. 3/8

Ans is D, probability of not drawing a blue is not dependent on the position, considering that there is no restriction or criterion defined on sequence of draws any ball can be drawn before 7th not blue ball condition. Therefore it should be Redballs/totalballs i.e 5/8.
_________________

Piyush K
-----------------------
Our greatest weakness lies in giving up. The most certain way to succeed is to try just one more time. ― Thomas A. Edison
Don't forget to press--> Kudos

Manager
Joined: 22 Mar 2013
Posts: 102
Location: India
Concentration: General Management, Strategy
GPA: 3.51
WE: Information Technology (Computer Software)
Followers: 0

Kudos [?]: 23 [0], given: 31

Re: New Set of Mixed Questions!!! [#permalink]  25 Sep 2013, 05:02
4.
Volume of pool = V
Water added in pool BY rain in 6 hours = 3x6=18liters
Standard pump output rate (V/4) for 6 hours V6/4

Thus
V + 18 - V6/4 =0

V=36
_________________

Piyush K
-----------------------
Our greatest weakness lies in giving up. The most certain way to succeed is to try just one more time. ― Thomas A. Edison
Don't forget to press--> Kudos

Re: New Set of Mixed Questions!!!   [#permalink] 25 Sep 2013, 05:02
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