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Manager
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Next Meeting [#permalink] New post 22 Apr 2006, 05:49
Similar to
http://www.gmatclub.com/phpbb/viewtopic.php?t=28558

Two persons agree to meet at between 2 PM to 3 PM, but each of them will wait 10
minutes for the late comer. What is the probability that they will meet ?
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 [#permalink] New post 22 Apr 2006, 11:21
11/36

the explanation is the same
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 [#permalink] New post 22 Apr 2006, 11:32
deowl wrote:
the explanation is the same


Well, there were a lot of different explanations :-D
You're answer is correct. What approach did you choose?
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 [#permalink] New post 22 Apr 2006, 11:43
Well, now I see that my approach is really different...
anyway, draw a 6x6 grid where each cell is a 10 minutes interval
assume the y-axis is for man Y and the x-axis is for man X.

Now you have to find the ratio of the area that represent different posibilities they meet to the total area of the grid. No math here , just cell counting ;)

what we get is 11/36
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 [#permalink] New post 22 Apr 2006, 12:00
deowl wrote:
No math here , just cell counting ;)


You're approach is interesting, but I guess it's much
easier with at least a bit of math.

The answer is 1 - (1 - 10/60)^2 = 11/36.
For the other exercise, it was 1 - (1 - 30/120)^2 = 7/16.

I found this by trying and thinking a bit.

As with the other similar exercise, the problem can
be compared with:

If 2 dice are thrown, what is the possibility that at
least one shows a specific number.

In our example with the meeting, it could be translated to

If 2 peeple meet, what is the possibility that at least
one arrives within a range to a specific time (that for
each of them represents the arrival of the other one).

I'm not totally sure with the comparison, but I testet the
formula with the computer for different values and the results
are correct.
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 [#permalink] New post 22 Apr 2006, 16:03
well done ccax, i'll keep that formula in mind, even though I still need to understand the logic behind
  [#permalink] 22 Apr 2006, 16:03
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