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noel's quizz

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Manager
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noel's quizz [#permalink] New post 19 Aug 2003, 03:46
hello, guys

this problem comes from noel's site - http://www.geocities.com/gmatcrew/noel.htm (hope, everybody knows that person from bweek-forums).

if x and y are prime, is xy odd?
1. x-y is even
2. x/y is not an integer

i voted for A. obviously, only subtracting prime from prime gives us even (you don't count 2, since it will contradict with statement 1). thus, 1 is suff. statement 2 is not suff., because we don't know either it 2/3 or 3/5 or whatever. since prime 2 is a key here and we are not sure whether it exists or not, statement 2 is not suff. but noel says, i am wrong :shock:

ps. unfortunatelly, it is diagnostic test and noel does not give any right answer. he just agrees with you, if you are right ('ok') or puts question mark '?' if you are wrong...
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 [#permalink] New post 19 Aug 2003, 04:16
I also fell for the trap!
What a good question?

My answer is E.

For 1) Assume X=Y=2 ; XY=4 = EVEN
Assume X=3 Y=5 ; XY=15 = ODD
Not Suff.


Keep posting questions like this.

I hope, we won't make such a mistakes in the real exam!
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Re: noel's quizz [#permalink] New post 19 Aug 2003, 07:43
surat wrote:
hello, guys

this problem comes from noel's site - http://www.geocities.com/gmatcrew/noel.htm (hope, everybody knows that person from bweek-forums).

if x and y are prime, is xy odd?
1. x-y is even
2. x/y is not an integer

i voted for A. obviously, only subtracting prime from prime gives us even (you don't count 2, since it will contradict with statement 1). thus, 1 is suff. statement 2 is not suff., because we don't know either it 2/3 or 3/5 or whatever. since prime 2 is a key here and we are not sure whether it exists or not, statement 2 is not suff. but noel says, i am wrong :shock:

ps. unfortunatelly, it is diagnostic test and noel does not give any right answer. he just agrees with you, if you are right ('ok') or puts question mark '?' if you are wrong...



I'll go with E

(1) gives us that x and y are either both odd, or x=y
If its the former, then x*y is odd. But if its the latter, then we cannot say since x=y=2 gives x*y=even

(2) is trivial since x is prime and does not help us answer the problem

Therefore, E

Now
Re: noel's quizz   [#permalink] 19 Aug 2003, 07:43
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