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non terminating decimal [#permalink]
 20 Aug 2009, 15:40
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8103/x is a non terminating deciml.Which of the following could be a value of x? 2,5,9,12,15 Allrite,2 and 5 are out coz they give rise to terminatig decimals..What is the conceptual way of solving this sum?
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Re: non terminating decimal [#permalink]
20 Aug 2009, 19:51
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8103=3*2701 and when 12=3*4, 15=3*5 are divisors, the results for any 3n are always terminating. the answer is 9.
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Director
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Re: non terminating decimal [#permalink]
26 Sep 2009, 04:20
I am sorry i didnt follow the explanation..could somebody please explain in detail
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Re: non terminating decimal [#permalink]
26 Sep 2009, 09:09
The answer is 9. It is the property of number nine. "Any number when divided by nine gives a number which has non terminating value"Hope it helps..!! 
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Re: non terminating decimal [#permalink]
26 Sep 2009, 11:13
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8103/x is a non terminating deciml.Which of the following could be a value of x?
2,5,9,12,15
Let me try to explain. Now usually numbers when divided by 3 or a multiple of 3 are non terminating. This should be checked after reducing the number to the lowest form i.e cancelling out any common factors. Now we can boil down to just three values that can result in non-terminating decimals. 9,12 and 15 since all are multiple of 3. But 8103 is a multiple of 3. Hence we could cancel out the 3 between numerator and denominator. Thus 8103 when divided by 9 , 12 and 15 will reduce to 2701/3, 2701/4 and 2701/5. Now if we check, only the first one is divided by 3 but the other two are divided by 4 and 5 which will result in terminating decimals. Thus 9 is the answer.
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Re: non terminating decimal
[#permalink]
26 Sep 2009, 11:13
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