number of stamps : GMAT Problem Solving (PS)
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 24 Jan 2017, 13:43

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# number of stamps

Author Message
TAGS:

### Hide Tags

Director
Joined: 11 Sep 2006
Posts: 514
Followers: 2

Kudos [?]: 36 [0], given: 0

### Show Tags

13 Nov 2006, 19:25
00:00

Difficulty:

(N/A)

Question Stats:

33% (00:00) correct 67% (01:04) wrong based on 9 sessions

### HideShow timer Statistics

The number of stamps that Kaye and Alberto had wer in the ration 5:3, respectively. After Kaye gave Alberto 10 of her stamps, the ratio of the number Kaye had to the number Alberto had was 7:5. As a result of this gift, Kaye had how many more stamps than Alberto?
20
30
40
60
90

I know how to do these, and yet I keep getting the wrong answer on this one...
_________________

...there ain't no such thing as a free lunch...

Manager
Joined: 29 Aug 2006
Posts: 157
Followers: 1

Kudos [?]: 6 [0], given: 0

### Show Tags

13 Nov 2006, 19:37
I get C

K=Kayle
A=Alberto

K/A =5/3--------(1)

(K-10)/(A+10)= 7/5------(2)

Substitute values from 1 in 2,

A=90
K=150

As a result of the gift, Alberto has A+10=100 and Kayle has K-10=140 and the diff between the two is 40.
Director
Joined: 11 Sep 2006
Posts: 514
Followers: 2

Kudos [?]: 36 [0], given: 0

### Show Tags

13 Nov 2006, 19:56
Priyah, I am terribly sorry to be so dense, but from whence did you derive your numerical values for K and A??
_________________

...there ain't no such thing as a free lunch...

Manager
Joined: 29 Aug 2006
Posts: 157
Followers: 1

Kudos [?]: 6 [0], given: 0

### Show Tags

13 Nov 2006, 20:16
K/A =5/3--------(1)

(K-10)/(A+10)= 7/5------(2)

eqn 2 can be simplified to
5(K-10)=7(A+10)

Now substitute K=5A/3 from eqn 1 in 2 and u will get the values.
25A-150=21A+210
4A=360
A=90
GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5062
Location: Singapore
Followers: 30

Kudos [?]: 358 [0], given: 0

### Show Tags

14 Nov 2006, 00:01
Total number of stamps = x
# of stamps kaye owned = 5x/8
# of stamps Alberto owned =3x/8

New # of stamps kaye own = 5x/8 - 10
New # of stamps Alberto own = 3x/8 + 10

Ratio =

7/5 = (5x-80)/8 * 8/(3x+80)
7/5 = (5x-80)/(3x+80)
21x + 560 = 25x - 400
4x = 960
x = 240

Kaye now has 140
Alberto now has 100

So Kaye has 40 more stamps now.
Senior Manager
Joined: 01 Oct 2006
Posts: 497
Followers: 1

Kudos [?]: 32 [0], given: 0

### Show Tags

14 Nov 2006, 00:14
Let Kaye have x stamps alberto have x:y = 5:3 and after giving 10 stamps x-10:y+10 = 7:5
Put x =5y/3 in the eq above and solve to get value of y as 90 and then x=5y/3=150.
After giving 10 x=140 and y=100.
Thus kaye has 40 more stamps then alberto
SVP
Joined: 05 Jul 2006
Posts: 1743
Followers: 6

Kudos [?]: 318 [0], given: 49

### Show Tags

14 Nov 2006, 04:01
The number of stamps that Kaye and Alberto had wer in the ration 5:3, respectively. After Kaye gave Alberto 10 of her stamps, the ratio of the number Kaye had to the number Alberto had was 7:5. As a result of this gift, Kaye had how many more stamps than Alberto?
20
30
40
60
90

kaye stamps = 5x

Alberto stamps = 3x

after transaction

kay = 5x-10

Alberto = 3x+10

kaye/alberto = 5x-10/3x+10 = 7/5

25x-50 = 21x+70

4x = 120

x = 30

Kaye after = 140

alberto = 100

Director
Joined: 11 Sep 2006
Posts: 514
Followers: 2

Kudos [?]: 36 [0], given: 0

### Show Tags

14 Nov 2006, 07:10
OA is C - and I get it now! As always, thank you all very much...
_________________

...there ain't no such thing as a free lunch...

Manager
Joined: 12 Oct 2006
Posts: 81
Location: NJ, US
Followers: 1

Kudos [?]: 0 [0], given: 0

### Show Tags

14 Nov 2006, 09:35
This is a great problem because while it is not real tough it is real time consuming. Does anyone know any shortcuts?
Senior Manager
Joined: 29 Jan 2011
Posts: 367
Followers: 0

Kudos [?]: 201 [0], given: 87

### Show Tags

04 Jul 2011, 03:04
Can any one post the solution to solve this using random numbers? Since the ratio is 5: 3

And lets say I choose the total stamps to be 15... Then Kaye might have 15/5 = 3 stamps and Alberto might have 15/3 = 5 stamps ...but 3/5 is not 5:3? What am I doing wrong here?Can someone please help
Current Student
Joined: 26 May 2005
Posts: 565
Followers: 18

Kudos [?]: 204 [0], given: 13

### Show Tags

04 Jul 2011, 03:37
siddhans wrote:
Can any one post the solution to solve this using random numbers? Since the ratio is 5: 3

And lets say I choose the total stamps to be 15... Then Kaye might have 15/5 = 3 stamps and Alberto might have 15/3 = 5 stamps ...but 3/5 is not 5:3? What am I doing wrong here?Can someone please help

im sure u r following Manhattan gmat... they always ask u to pick smart numbers..

15 is not a smart number..U just cant pick it and reduce 10 from it and have a rati of 7
the current ratio is 5:3 and after giving away 10 .. the ratio becomes 7:5
picking numbers satisfying this is condition is tough unless ur very good at multiplication and see numbers very easily.
It took me 15 seconds to guess 5:3 shud be 150:90
so its better that u follow the std method;

5x-10/3x+10 = 7/5 , X = 30
Senior Manager
Joined: 29 Jan 2011
Posts: 367
Followers: 0

Kudos [?]: 201 [0], given: 87

### Show Tags

04 Jul 2011, 03:47
sudhir18n wrote:
siddhans wrote:
Can any one post the solution to solve this using random numbers? Since the ratio is 5: 3

And lets say I choose the total stamps to be 15... Then Kaye might have 15/5 = 3 stamps and Alberto might have 15/3 = 5 stamps ...but 3/5 is not 5:3? What am I doing wrong here?Can someone please help

im sure u r following Manhattan gmat... they always ask u to pick smart numbers..

15 is not a smart number..U just cant pick it and reduce 10 from it and have a rati of 7
the current ratio is 5:3 and after giving away 10 .. the ratio becomes 7:5
picking numbers satisfying this is condition is tough unless ur very good at multiplication and see numbers very easily.
It took me 15 seconds to guess 5:3 shud be 150:90
so its better that u follow the std method;

5x-10/3x+10 = 7/5 , X = 30

Yes, I was referring to smart numbers ..Looks like its difficult to solve this using smart numbers?
Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 7132
Location: Pune, India
Followers: 2140

Kudos [?]: 13715 [0], given: 222

### Show Tags

05 Jul 2011, 02:57
siddhans wrote:

Yes, I was referring to smart numbers ..Looks like its difficult to solve this using smart numbers?

I would strongly suggest that you should stick to the method of solving which is quite straight forward as shown by yezz above. You may not be able to put your finger on the right numbers for a long time so its a gamble.
Nevertheless, if you do insist on using numbers to figure out, pick numbers smartly (I don't know what you mean by smart numbers except LCM/HCF is some cases and 100 in percentages.)

Let me explain what I mean by 'picking numbers smartly'
I see that the given ratio is 5:3
So actual numbers could be K-10 and A-6. If K gives 10 to A, ratio becomes 0:16. K has less than A but we need K to retain more than A so that the ratio is 7:5.
Actual numbers could be K-50 and A-30. If K gives 10 to A, ratio becomes 40:40 i.e. 1:1. The ratio has increased from before. Both have equal numbers. If the common multiplier chosen is less than 10, K will have less than A. If the common multiplier chosen is more than 10, K will retain more than A. So we need to go higher up.
Actual numbers could be K-100 and A-60. If K gives 10 to A, ratio becomes 9:7. Still less than 7:5. So we need to go further up
Actual numbers could be K-150 and A-90. If K gives 10 to A, ratio becomes 7:5.
There is a logic you are following to reach to the answer. Say, if I had jumped to K-200, A-120 directly, the new ratio would be 19:13 which is greater than 7:5 so I would try and find something in between K-100 and K-200. But using this approach, I am hoping that the multiplier will be an easy round number. Though it is true in most cases for GMAT, I would still not use this approach considering that the alternative standard method is quick and clean.
_________________

Karishma
Veritas Prep | GMAT Instructor
My Blog

Get started with Veritas Prep GMAT On Demand for \$199

Veritas Prep Reviews

Re: number of stamps   [#permalink] 05 Jul 2011, 02:57
Similar topics Replies Last post
Similar
Topics:
1 Cecilia, Robbie, and Briony all bought stamps. The number of stamps Ce 3 28 Feb 2016, 10:46
2 Alice has 3 times the number of stamps t that Doris does an 5 21 Oct 2012, 07:10
103 The number of stamps that Kaye and Alberto had were in the 23 27 Jul 2010, 12:25
6 The number of stamps that Kaye and Alberto had were in the ration of 5 6 27 Sep 2009, 23:43
9 The number of stamps Kaye and Alberto had were in the ratio 4 29 Sep 2008, 05:19
Display posts from previous: Sort by