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Numbers property Question [#permalink] New post 16 Jun 2004, 14:03
Hey gang, does anyone know a systematic way to solve to following problem:


For any numbers a and b, a*b=a+b-ab, if a*b=0, which of the following CANNOT be a value of b?

(A) 2
(B) 1
(C) 0
(D) -1
(E) -3/2

Thanks for your help
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 [#permalink] New post 16 Jun 2004, 14:05
did you mean, if ab not equal to 0
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 [#permalink] New post 16 Jun 2004, 14:25
Praet,
ab is equal to 0, this question came from GMAT #55 paper ed.
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 [#permalink] New post 16 Jun 2004, 18:04
Think it's B........!!
0=a+b+ab
=>a = b/b-1
Hence b cannot be 1 since that would yield 'a' as undefined..........!!
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 [#permalink] New post 16 Jun 2004, 18:07
Oops I forgot to login......BTW the equation shud be 0 = a+b-ab and that would yield a = b/b-1!!!
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Re: Numbers property Question [#permalink] New post 17 Jun 2004, 07:21
Roc-a-fella wrote:
Hey gang, does anyone know a systematic way to solve to following problem:


For any numbers a and b, a*b=a+b-ab, if a*b=0, which of the following CANNOT be a value of b?

(A) 2
(B) 1
(C) 0
(D) -1
(E) -3/2

Thanks for your help


B, of course:

if b = 1, then a + b - ab = 1 != 0.
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 [#permalink] New post 18 Jun 2004, 17:45
note a*b there is just notation (similar to those x bar probelms) and just means f(a,b).

B is corect.

Just substitue values and see if the solution contradicts any known stuff.
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  [#permalink] 18 Jun 2004, 17:45
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