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# Numbers property Question

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Intern
Joined: 04 Jun 2004
Posts: 8
Location: Gmat Hell
Followers: 0

Kudos [?]: 19 [0], given: 0

Numbers property Question [#permalink]  16 Jun 2004, 13:03
Hey gang, does anyone know a systematic way to solve to following problem:

For any numbers a and b, a*b=a+b-ab, if a*b=0, which of the following CANNOT be a value of b?

(A) 2
(B) 1
(C) 0
(D) -1
(E) -3/2

CEO
Joined: 15 Aug 2003
Posts: 3469
Followers: 61

Kudos [?]: 701 [0], given: 781

did you mean, if ab not equal to 0
Intern
Joined: 04 Jun 2004
Posts: 8
Location: Gmat Hell
Followers: 0

Kudos [?]: 19 [0], given: 0

Praet,
ab is equal to 0, this question came from GMAT #55 paper ed.
Joined: 31 Dec 1969
Location: India
Concentration: General Management, Strategy
GMAT 1: 710 Q49 V0
GMAT 2: 740 Q40 V50
GMAT 3: 700 Q48 V38
GPA: 3.6
Followers: 0

Kudos [?]: 88 [0], given: 87110

Think it's B........!!
0=a+b+ab
=>a = b/b-1
Hence b cannot be 1 since that would yield 'a' as undefined..........!!
Senior Manager
Joined: 05 Feb 2004
Posts: 290
Location: USA
Followers: 1

Kudos [?]: 3 [0], given: 0

Oops I forgot to login......BTW the equation shud be 0 = a+b-ab and that would yield a = b/b-1!!!
Manager
Joined: 07 May 2004
Posts: 183
Location: Ukraine, Russia(part-time)
Followers: 2

Kudos [?]: 8 [0], given: 0

Re: Numbers property Question [#permalink]  17 Jun 2004, 06:21
Roc-a-fella wrote:
Hey gang, does anyone know a systematic way to solve to following problem:

For any numbers a and b, a*b=a+b-ab, if a*b=0, which of the following CANNOT be a value of b?

(A) 2
(B) 1
(C) 0
(D) -1
(E) -3/2

B, of course:

if b = 1, then a + b - ab = 1 != 0.
Manager
Joined: 02 Jun 2004
Posts: 154
Location: san jose,ca
Followers: 3

Kudos [?]: 18 [0], given: 0

note a*b there is just notation (similar to those x bar probelms) and just means f(a,b).

B is corect.

Just substitue values and see if the solution contradicts any known stuff.
_________________

GS
No excuses - Need 750!!!

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