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Re: Numbers questions [#permalink]
1
Kudos
pkmme wrote:
the answer is correct.


pkmme - Don't be shy to give a kudos then 8-)
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Re: Numbers questions [#permalink]
puneetj wrote:
pkmme wrote:
the answer is correct.


pkmme - Don't be shy to give a kudos then 8-)


given u njoy:)
its 8
i use CRT method

3^21*6^55/10

(3^2)10*3 *6^55
(-1)^10*3*6/10
18/10 =8
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Re: Numbers questions [#permalink]
when a number is divided by 10 , last digit is the remainder.

so we have to find the unit digit of the given expression


( 3^(21)*6^(55))/10


3 has cyclicity of 4 => 3^(21) will have same unit digit as 3^1 = 3

unit digit of 6^any positive number = 6

=> remainder of ( 3^(21)*6^(55))/10 = remainder of (3*6/10) = remainder of (18/10)

= 8
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Re: Numbers questions [#permalink]
sudhir18n wrote:
puneetj wrote:
pkmme wrote:
the answer is correct.


pkmme - Don't be shy to give a kudos then 8-)


given u njoy:)
its 8
i use CRT method

3^21*6^55/10

(3^2)10*3 *6^55
(-1)^10*3*6/10
18/10 =8



Thank you Sudhir....still waiting for a one from pkmme
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Re: Numbers questions [#permalink]
3 with exponential power raised repeats after 4.

thus 3^21 will have units digit = 3
also, 6 with exponential power raised will always provide 6 in the units digit.

thus, 3*6 = 18.

remainder = 8.



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