Each digit in the 2 digit number G is halved to form a new 2 digit number H.Which of the following could be the sum of G and H?
Say H=xy [x is the ten's place digit after being halved and y is the unit's place digit after being halved]
Possible values of 2x=2,4,6,8; 2y=0,2,4,6,8
Possible values of x=1,2,3,4; y=0,1,2,3,4
Thus, the sum must be a multiple of 3; options C and E are out.
Let's try other options:
A. 3(10x+y)=153 i.e. 10x+y=51 i.e. 10*5+1=51; x=5(Not a possible value of x) and y=1
B. 3(10x+y)=150 i.e. 10x+y=50 i.e. 10*5+0=50; x=5(Not a possible value of x) and y=0
D. 3(10x+y)=129 i.e. 10x+y=43 i.e. 10*4+3=43; x=4(Possible) and y=3(Possible)
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