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Of a group of people surveyed, 75% have a computer, 62% have

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Of a group of people surveyed, 75% have a computer, 62% have [#permalink] New post 23 Feb 2006, 05:23
Of a group of people surveyed, 75% have a computer, 62% have a cd burner. What percent of the people have a computer but not a cd burner?

I. 11% of the people have a cd burner but not a computer
II. The number of people who have both is 3 times the number of people that have neither
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Re: computers [#permalink] New post 23 Feb 2006, 07:29
joemama142000 wrote:
Of a group of people surveyed, 75% have a computer, 62% have a cd burner. What percent of the people have a computer but not a cd burner?

I. 11% of the people have a cd burner but not a computer
II. The number of people who have both is 3 times the number of people that have neither


joemama142000, you are the source of questions. that si gr8. your questions are real gmat type questions. what is the source?

i go with B.

75-3x+62-3x+x=100
x = 37/2=18.5%
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 [#permalink] New post 23 Feb 2006, 07:50
I am not sure but A for me.Used venn diagram it is 24 %
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 [#permalink] New post 23 Feb 2006, 08:09
I think it is d

I suff -> if 11% have a cd burner but not a computer than 51% (62%-11%) have both -> thereof 24% have only a computer

II suff
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 [#permalink] New post 23 Feb 2006, 09:30
I think D. Although I didn't get same percentage for people having a computer but no burner. :roll:
I. Venn Diagram 24%
2. 75-3x+3x+62-3x+x
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 [#permalink] New post 23 Feb 2006, 09:55
I got D but with diff values


I.
Both + Burner/no Comp = 62
Both + no Burner/Comp = 75

From I, Burner/no Comp = 11,
Both + 11 = 62
Both = 51

51 + no Burner/Comp = 75
no Burner/Comp = 24
SUFF

II.

Both = 3(Neither)
Both + Burner/no Comp = 62
Both + no Burner/Comp = 75

62 + 75 - 3(Neither) + Neither = 100
Neither = 37/2
Both = 3(37/2)

no Burner/Comp = 75-3(37/2)
SUFF
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 [#permalink] New post 23 Feb 2006, 10:31
I go with D too..

But my only doubt is this.

I have never seen a DS problem with answer D and the 2 conditions not leading to the same answer.

here our answers are different. !!
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 [#permalink] New post 23 Feb 2006, 14:04
i have my doubts for b -> it just mentions numbers and not % can we solve it anyway? i am not sure but i think Stat I and Stat II should come to the same result or?
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Re: computers [#permalink] New post 23 Feb 2006, 15:50
joemama142000 wrote:
Of a group of people surveyed, 75% have a computer, 62% have a cd burner. What percent of the people have a computer but not a cd burner?

I. 11% of the people have a cd burner but not a computer
II. The number of people who have both is 3 times the number of people that have neither


I think it is A because this is a trick question. tomg brought up a good point

the second is only talking about numbers and not percentages.


there for you can't use 3x and x. in that equation for the venn diagram
for all we know it can be 1 and 3 or 3 and 9 or whatever. The answer will result in different numbers.

plug in numbers to see for yourselves

G1+ G2+N-B=T
75+62+x-3x=100
---------1,3
---------3,9



btw all of my stuff is from either og11, 1000series, 800score, or other forum posts.
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 [#permalink] New post 23 Feb 2006, 19:18
Own computer only: 75-n
Own computer and cd burner: n
Own cd burner only but no computer (strange but this is just math): 62-n
Neither: n-37

1) Sufficient. We can work out the number of people who have both, and then subtract that from 75%.

2) Let x be number of people surveyed
n/100(x) = 3 * (n-37)/100 * x
x can be cancelled from both sides. The same for 1/100

n = 3(n-37)
Can solve for n.

Sufficient.

Ans D
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 [#permalink] New post 23 Feb 2006, 21:29
It must be D.

Statement1 is easy and answer comes out to be 24%.

Statement2:
Let Total people surveyed = x
Then People who have computer = 0.75x
Peopel who have CD burner = 0.6x

Let people who have neither = a
Then peopel who have both = 3a

Then

0.75x-3a + 0.62x +a = x

Solve for a then we get a = 0.185x

So people who have both = 3 * 0.185x = 0.555x

Now people who have computer but not a cd burner = 0.75x - 0.555x = 0.195x i.e 19.5 %.

But this is among few DS problems that results in two different answer from two statements.
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 [#permalink] New post 23 Feb 2006, 22:02
Me for A since second statement does not speak in terms of %s.
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Re: computers [#permalink] New post 24 Feb 2006, 21:45
Professor wrote:
joemama142000 wrote:
Of a group of people surveyed, 75% have a computer, 62% have a cd burner. What percent of the people have a computer but not a cd burner?

I. 11% of the people have a cd burner but not a computer
II. The number of people who have both is 3 times the number of people that have neither

i go with B.

75-3x+62-3x+x=100
x = 37/2=18.5%

sorry guys. i didnot read the question properly so i overlooked it. i should correct it.

from i,
computer =75
cd =62
only cd= 11
c+cd= 62-11=51
only computer = 75-51=24
so the percent of the people who have a computer but not a cd burner = 24

from ii,
nither = x
both = 3x

c+cd- both + nither = 100
75 + 62 -3x + x = 100
2x = 137-100
x = 37/2

this also gives the answer but the answers are contradictory to each other. therefore, this question is also poorly worded.
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 [#permalink] New post 28 Feb 2006, 03:02
I think its D.

1. Can use Venn Diagrams
2. Can use extentionsion of venn diagrams with the additional data given.

Whats the OA?
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 [#permalink] New post 28 Feb 2006, 08:18
Good question. Must Know OA :o I go with A.
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 [#permalink] New post 28 Feb 2006, 10:02
D is right.

I have never seen an official problem in which the two statements contradict each other.
  [#permalink] 28 Feb 2006, 10:02
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