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Of the 25 cars sold at a certain dealership yesterday, some [#permalink]
27 Sep 2009, 06:11

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00:00

A

B

C

D

E

Difficulty:

25% (medium)

Question Stats:

79% (01:45) correct
21% (00:48) wrong based on 171 sessions

Of the 25 cars sold at a certain dealership yesterday, some had automatic transmission and some had antilock brakes. How many of the cars had automatic transmission but not antilock brakes?

(1) All of the cars that had antilock brakes also had automatic transmission.

(2) 2 of the cars had neither automatic transmission, nor antilock brakes.

Re: Of the 25 cars sold at a certain dealership yesterday, some [#permalink]
30 Dec 2013, 01:28

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yangsta8 wrote:

Of the 25 cars sold at a certain dealership yesterday, some had automatic transmission and some had anti-lock brakes. How many of the cars had a automatic transmission but not antilock brakes?

(1) all of the cars that had anti-lock brakes also had an automatic transmission (2) 2 of the cars had neither automatic transmission nor anti-lock brakes

I got the answer right but it took me quite a while was wondering if anyone had a suggestion of using tables, venn diagram etc?

Attachment:

untitled.PNG [ 12.25 KiB | Viewed 2929 times ]

Look at the attachment above .

ALB: Anti Lock Brakes NALB: No Anti Lock Brakes AT: Automatic Transmission NAT: No Automatic Transmission

We need to find the value of x ie.

With given data we can only find x+y =23 but not x.

Hence Answer is E _________________

“If you can't fly then run, if you can't run then walk, if you can't walk then crawl, but whatever you do you have to keep moving forward.”

Re: Of the 25 cars sold at a certain dealership yesterday, some [#permalink]
16 Oct 2009, 17:44

1

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Diagram:

An NoA T ......... ___________ Auto |___|___|___| Man |___|___|___| T........|___|___|___|

-I hope that came out. If not: You need to make a box with 9 square so there are 3 rows, 3 columns. Label the columns as Antilock, No Antilock, and Total... and the rows at Automatic, Manual, and Total.

-In the bottom right cube, fill in the total of 25 cars. This was given to you. Then, plug in numbers, and sum columns and rows. Here is how mine came out for this problem while looking to see if both statements together can work.

Re: Of the 25 cars sold at a certain dealership yesterday, some [#permalink]
27 Sep 2009, 07:03

E let A=all of the cars that had an automatic transmission.. B=all of the cars that had anti-lock brakes SI just tells us that B is a part of A...not suffi SII tells us AUB, which is set A itself is 23..not suffi combining two... still not sufficient as we require A-B

Re: Of the 25 cars sold at a certain dealership yesterday, some [#permalink]
29 Dec 2013, 04:48

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Re: Of the 25 cars sold at a certain dealership yesterday, some [#permalink]
20 Oct 2014, 01:24

Expert's post

3

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angelfire213 wrote:

Of the 25 cars sold at a certain dealership yesterday, some had automatic transmission and some had antilock brakes. How many of the cars had automatic transmission but not antilock brakes?

(1) All of the cars that had antilock brakes also had automatic transmission.

(2) 2 of the cars had neither automatic transmission, nor antilock brakes.

sigh, lots of questions today.

Can someone explain this to me. If 1. ALL the cars that had antilock also had automatic trans.. and 2. 2 of the cars had neither auto nor anti lock

Does that not mean that 23 cars had anti-lock in which case 23 cars also had auto...and thus filling in all the boxes, this would be solvable?

No. All of the cars that had antilock brakes also had automatic transmission means that 0 cars have antilock brakes but no automatic transmission. Check the matric below:

Attachment:

Untitled.png [ 5.51 KiB | Viewed 1264 times ]

We need to find the value of yellow box, which is not possible from the info we have. _________________

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