jimmyjamesdonkey wrote:

Of the 2500 votes participating in a local election, three times as many voted for candidate A as for candidate B, and twice as many people voted for candidate A as for candidate C. If each voter chose either candidate A, B, or C, or abstained, and 300 voters abstained, how many people voted for candidate C?

400

600

1200

1800

2000

Know how to solve using brute force. Looking for a equation and explanation of how to solve.

Thanks. OA to come.

Easy.

kirakira solved in terms of A and plaguerabbit solved in terms of C.

This is how to do it in terms of B.

Given

A=3B

A=2C

Equation:

A+B+C=2500-300

A+B+C=2200

3B + B + C = 2200

2C=3B

C=3B/2

therefore...

3B + B + 3B/2 = 2200

multiply entire equation by 2 to get rid of denominator

6B + 2B + 3B = 2200

11B = 2200

B=200

C= 3B = 3*200 = 600