Of the 2500 votes participating in a local election, three times as many voted for candidate A as for candidate B, and twice as many people voted for candidate A as for candidate C. If each voter chose either candidate A, B, or C, or abstained, and 300 voters abstained, how many people voted for candidate C?
Know how to solve using brute force. Looking for a equation and explanation of how to solve.
Thanks. OA to come.
kirakira solved in terms of A and plaguerabbit solved in terms of C.
This is how to do it in terms of B.
3B + B + C = 2200
3B + B + 3B/2 = 2200
multiply entire equation by 2 to get rid of denominator
6B + 2B + 3B = 2200
11B = 2200
C= 3B = 3*200 = 600