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# Of the 60 animals on a certain farm, 2/3 are either pigs or

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Manager
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Of the 60 animals on a certain farm, 2/3 are either pigs or [#permalink]  04 May 2006, 21:31
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Of the 60 animals on a certain farm, 2/3 are either pigs or cows. How many of the animals are cows?
(1) The farm has more than twice as many cows as it has pigs.
(2) The farm has more than 12 pigs.
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VP
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C?

There are 27 cows

(1) Many combinations of cows/pigs would satisfy this equation
(2) Clearly infufficient

(1) + (2) P = 13, C = 27 ==> OK
P = 14, C = 26 ==> (1) FAILS
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Director
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Of the 60 animals on a certain farm, 2/3 are either pigs or cows
Not clear what about the 1/3?
E for me
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Director
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Why is it not A?

2/3 are either pigs or cows.

P + C = 40

Statement 1 gives that there are twice the no of cows

ie. C = 2P

from this we can get the no of cows.
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2/3(60) = 40 either pigs or cows
# of pigs = P
# of cows = 40-p

St1:
40-p = 2p

Can solve for p, then solve for # of cows. Sufficient.

St2:
Sufficient. We know p and therefore can calculate # of cows, which is 40-p.

Ans D

** I assume the remaining 1/3 are neither pigs nor cows.
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ywilfred wrote:
2/3(60) = 40 either pigs or cows
# of pigs = P
# of cows = 40-p

St1:
40-p = 2p

Can solve for p, then solve for # of cows. Sufficient.

St2:
Sufficient. We know p and therefore can calculate # of cows, which is 40-p.

Ans D

** I assume the remaining 1/3 are neither pigs nor cows.

But from statement 2 we only know that no of pigs is MORE than 12. It can be 13, 14 or even 39.
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remgeo wrote:
Why is it not A?

2/3 are either pigs or cows.

P + C = 40

Statement 1 gives that there are twice the no of cows

ie. C = 2P

from this we can get the no of cows.

The statement says 'more than twice as many'
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Manager
Joined: 27 Mar 2006
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I say E...since exact number can not be determined...all we know is it is more than a certain value
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