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Of the families in a certain community, 75% have an oven,

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Senior Manager
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Of the families in a certain community, 75% have an oven, [#permalink]

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New post 20 Aug 2006, 01:45
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Of the families in a certain community, 75% have an oven, 62% have a dish drier. What percent of them have an oven but do not have dish drier?

1). 11% of the families have a dish drier but do not have an oven.
2). The number of the families that have both is three times that of the families that have neither.

Shouldnt the answer to this question be D. In the question bank it said that 2 gave a number not a percentage. So the answer it gave was A

I think for number 2 you can assign variables that eventually can be cancelled out.
let N be number of families
let Y% be the percentage of families which does not have an oven nor a dish dryer

100%n-y%n=75%n+62%n-3y%n--> N can be cancelled thus leaving one variable. Am i correct?
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New post 20 Aug 2006, 01:54
:no

Answer should be A.

You are right for statement 1 but statement 2 gives you the NUMBER not the percentage and all other information is in percentages. Either everything should be in percentages or should be in numbers.
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SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

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New post 20 Aug 2006, 06:13
Statement 1 gives the percentage which is required. i.e 26 percent.

Statement 2 is insuff

Ans A
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New post 20 Aug 2006, 09:18
I think it should be A
Number cannoty have a percentage equivalent.
n(O) = 75%
n(D) = 62%
Watch this step :
Let the number of people haing both be 3x ~ 3y% - wrong assumption ..
:idea:

Number of people cannot be proportional to percentage of people

IT IS A
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New post 20 Aug 2006, 09:42
Yep... agree with A...

Number does not indicate percentage...

Cannot compute percentage based on the two numbers given...
  [#permalink] 20 Aug 2006, 09:42
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Of the families in a certain community, 75% have an oven,

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