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Of the families in City X in 1994, 40 percent owned a

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Manager
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Of the families in City X in 1994, 40 percent owned a [#permalink] New post 02 May 2006, 02:31
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Of the families in City X in 1994, 40 percent owned a personal computer. The number of families in City X owning a computer in 1998 was 30 percent greater than it was in 1994, and the total number of families in City X was 4 percent greater in 1998 than it was in 1994. What percent of the families in City X owned a personal computer in 1998 ?
A. 50%
B. 52%
C. 56%
D. 70%
E. 74%
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 [#permalink] New post 03 May 2006, 00:24
answer is B 52 %

let families in city x in 94 be 100 than the calculation are pretty easy
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 [#permalink] New post 03 May 2006, 01:06
1994:
# of families in City X = x
# of families in City X that own a PC = 0.4x

1998:
# of families in City X that own a PC = 0.52x
# of families in City X = 1.04x

% of families that own a pC = 0.52/1.04 = 50%
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 [#permalink] New post 04 May 2006, 02:04
Ans = A.

The easiest approach is to substitute numbers.

1994 population = 100
owning television = 40

Therefore, 1998 population = 104 (4% greater than 1994)
owning television = 52 (30% greater than 1994)

Percentage owning television in 1998 = (52/104) * 100 = 50%
  [#permalink] 04 May 2006, 02:04
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Of the families in City X in 1994, 40 percent owned a

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