Of the families in City X in 1994, 40 percent owned a

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Of the families in City X in 1994, 40 percent owned a [#permalink]

02 May 2006, 03:31

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Of the families in City X in 1994, 40 percent owned a personal computer. The number of families in City X owning a computer in 1998 was 30 percent greater than it was in 1994, and the total number of families in City X was 4 percent greater in 1998 than it was in 1994. What percent of the families in City X owned a personal computer in 1998 ?
A. 50%
B. 52%
C. 56%
D. 70%
E. 74%

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03 May 2006, 01:24

answer is B 52 %

let families in city x in 94 be 100 than the calculation are pretty easy
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03 May 2006, 02:06

1994:
# of families in City X = x
# of families in City X that own a PC = 0.4x

1998:
# of families in City X that own a PC = 0.52x
# of families in City X = 1.04x

% of families that own a pC = 0.52/1.04 = 50%

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04 May 2006, 03:04

Ans = A.

The easiest approach is to substitute numbers.

1994 population = 100
owning television = 40

Therefore, 1998 population = 104 (4% greater than 1994)
owning television = 52 (30% greater than 1994)

Percentage owning television in 1998 = (52/104) * 100 = 50%

[#permalink] 04 May 2006, 03:04

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Of the families in City X in 1994, 40 percent owned a

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Of the families in City X in 1994, 40 percent owned a

Of the families in City X in 1994, 40 percent owned a

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