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Of the families in City X in 1994, 40 percent owned a

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Intern
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Of the families in City X in 1994, 40 percent owned a [#permalink] New post 10 Oct 2008, 11:09
Of the families in City X in 1994, 40 percent owned a personal computer. The number of families in City X owning a computer in 1998 was 30 percent greater than it was in 1994, and the total number of families in City X was 4 percent greater in 1998 than it was in 1994. What percent of the families in City X owned a personal computer in 1998?

A. 50%
B. 52%
C. 56%
D. 70%
E. 74%
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Re: computer [#permalink] New post 10 Oct 2008, 11:23
Let x be the number of families in City X in 1994.
40 percent who owned a pc in 1994 = .4x
people who owned a pc in 1998 = .4x * 1.3 = .52x
number of families in City X in 1998 = 1.04x

percent of families w/ pc in 1998 = .52x/1.04x = 1/2. Therefore 50%. The answer is A.
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Re: computer [#permalink] New post 10 Oct 2008, 11:29
Whenever you have percentage problem, its best to use numbers such as 100,1000 etc.

Let # of families in 1994 be 1000
1994
PC = 400, Family = 1000

1998
PC = 520 (400+0.30*400) , Family = 1040

520/1040 *100 = 50%

A
Re: computer   [#permalink] 10 Oct 2008, 11:29
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Of the families in City X in 1994, 40 percent owned a

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