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Of the families in City X in 1994, 40 percent owned a person

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Of the families in City X in 1994, 40 percent owned a person [#permalink] New post 09 Jun 2007, 19:33
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Question Stats:

72% (02:25) correct 28% (02:22) wrong based on 155 sessions
Of the families in City X in 1994, 40 percent owned a personal computer. The number of families in City X owning a computer in 1998 was 30 percent greater than it was in 1994, and the total number of families in City X was 4 percent greater in 1998 than it was in 1994. what percent of the families in City X owned a personal computer in 1998?

A. 50%
B. 52%
C. 56%
D. 70%
E. 74%
[Reveal] Spoiler: OA

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Last edited by Bunuel on 31 Jul 2013, 10:05, edited 2 times in total.
Added the OA.
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 [#permalink] New post 09 Jun 2007, 19:46
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The answer is A - 50%

Say a 100 families existed in 1994 then the number of families owning a computer in 1994 - 40
Number of families owning computer in 1998 = 40 * 130/100 = 52
Number of families in 1998 = 104

The percentage = 52/104 * 100 = 50%.
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Re: Q37: Of the families in City X in 1994, 40 percent owned a [#permalink] New post 31 Jul 2013, 09:07
jet1445 wrote:
Q37:
Of the families in City X in 1994, 40 percent owned a personal computer. The number of families in City X owning a computer in 1998 was 30 percent greater than it was in 1994, and the total number of families in City X was 4 percent greater in 1998 than it was in 1994. What percent of the families in City X owned a personal computer in 1998?

A. 50%
B. 52%
C. 56%
D. 70%
E. 74%


1994 = 40 families (40% of total)
1998 = 40 F * 30% = 12+40 = 52 families.

Population in 1994 = 100; 1998 = 104

==> 52/104 = 1/2 = 50%
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Re: Of the families in City X in 1994, 40 percent owned a person [#permalink] New post 11 Oct 2014, 04:17
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Re: Of the families in City X in 1994, 40 percent owned a person [#permalink] New post 15 Oct 2014, 23:20
Year .................. Family .................. Computer

1994 .................. 100 (Assume) ............. 40

1998 .................... 104 ......................... 40 + 40 * \frac{30}{100} = 52

Answer = A= \frac{52}{104} * 100 = 50%
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Re: Of the families in City X in 1994, 40 percent owned a person   [#permalink] 15 Oct 2014, 23:20
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