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Of the goose eggs laid at a certain pond, 2/3 hatched, and

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Of the goose eggs laid at a certain pond, 2/3 hatched, and [#permalink] New post 20 Jun 2008, 00:38
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Of the goose eggs laid at a certain pond, 2/3 hatched, and 3/4 of the geese that hatched from those eggs survived the first month. Of the geese that survived the first month, 3/5 did not survive the first year. If 120 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond?
A. 280
B. 400
C. 540
D. 600
E. 840
I tried solving it in this way
Let total eggs laid=x
then x*(2/3)*(3/4)*(3/5) is the no of eggs who didnt survive
so eggs who survived= x-3x/10=120
this doesnt give answer.
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Re: PS: goose eggs [#permalink] New post 20 Jun 2008, 00:44
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Based on the Q stem if total eggs were X then 3/4x2/3x2/5xX=120
Ans: 600
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Re: PS: goose eggs [#permalink] New post 20 Jun 2008, 01:14
ritula wrote:
Of the goose eggs laid at a certain pond, 2/3 hatched, and 3/4 of the geese that hatched from those eggs survived the first month. Of the geese that survived the first month, 3/5 did not survive the first year. If 120 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond?
A. 280
B. 400
C. 540
D. 600
E. 840
I tried solving it in this way
Let total eggs laid=x
then x*(2/3)*(3/4)*(3/5) is the no of eggs who didnt survive
so eggs who survived= x-3x/10=120
this doesnt give answer.

your ratios are wrong. they should be 1/3, 1/4 and 3/5
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Re: PS: goose eggs [#permalink] New post 20 Jun 2008, 01:31
ritula wrote:
Of the goose eggs laid at a certain pond, 2/3 hatched, and 3/4 of the geese that hatched from those eggs survived the first month. Of the geese that survived the first month, 3/5 did not survive the first year. If 120 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond?
A. 280
B. 400
C. 540
D. 600
E. 840
I tried solving it in this way
Let total eggs laid=x
then x*(2/3)*(3/4)*(3/5) is the no of eggs who didnt survive
so eggs who survived= x-3x/10=120
this doesnt give answer.


IMO D
My approach
let the total number of eggs laid be x
2/3 hathced = 2x/3
and 3/4 of the geese that hatched from those eggs survived the first month = x/2
Of the geese that survived the first month, 3/5 did not survive the first year(number who survived) = x/5
which is equal to 120
therefore
x = 600
HTH
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Re: PS: goose eggs [#permalink] New post 20 Jun 2008, 06:52
ritula wrote:
Of the goose eggs laid at a certain pond, 2/3 hatched, and 3/4 of the geese that hatched from those eggs survived the first month. Of the geese that survived the first month, 3/5 did not survive the first year. If 120 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond?
A. 280
B. 400
C. 540
D. 600
E. 840
I tried solving it in this way
Let total eggs laid=x
then x*(2/3)*(3/4)*(3/5) is the no of eggs who didnt survive
so eggs who survived= x-3x/10=120
this doesnt give answer.


I got D.

let t bee the total number of eggs laid. Of the tatal eggs laid, 2/3 hatched therfore 2/3t.
3/4 of the eggs that hatched survived the first month. 3/4 x 2/3t = 1/2t
3/5 did not survive the first year hence 3/5 x 1/2t = 3/10t
meaning 2/10t survived.
so it says 120 geese = 2/10t.

therefore to find the total number of eggs hatched will be 120 x 10/2t which is equal to 600.
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Re: PS: goose eggs [#permalink] New post 20 Jun 2008, 08:17
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ritula wrote:
2/3 hatched
3/4 of the geese survived
3/5 did not survive


This is a great example of what tricks thrown at you in the GMAT. Read carefully for the "not" modifiers. Not only in the full question, but in the question stem. They are testing more your ability to critically read than your ability to solve math problems.
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Re: PS: goose eggs [#permalink] New post 21 Jun 2008, 10:34
ok now i know wht mistake i was doing. Instead of the last protion, i was negating the whole stem. the OA is D indeed. thanks all for discussion
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Re: PS: goose eggs [#permalink] New post 23 Nov 2010, 07:15
You can also back solve this question by picking choices from answers ( makes life easier)
for example pick D =600
600*2/3=400 hatched
400*3/4=300 Survived first month
300*3/5=180 did not survive
Total survived=300-180=120

So we get answer from 600 i.e answer choice D
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Re: PS: goose eggs [#permalink] New post 23 Nov 2010, 09:37
ritula wrote:
Of the goose eggs laid at a certain pond, 2/3 hatched, and 3/4 of the geese that hatched from those eggs survived the first month. Of the geese that survived the first month, 3/5 did not survive the first year. If 120 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond?
A. 280
B. 400
C. 540
D. 600
E. 840
I tried solving it in this way
Let total eggs laid=x
then x*(2/3)*(3/4)*(3/5) is the no of eggs who didnt survive
so eggs who survived= x-3x/10=120
this doesnt give answer.


When you face a long text question in GMAT, try reading and analyzing one line at a time rather than trying to make sense of the whole question in a go. This is what I would do:

Of the goose eggs laid at a certain pond, 2/3 hatched, and 3/4 of the geese that hatched from those eggs survived the first month.
- This means 2/3 *3/4 = 1/2 of the eggs survived the first month.

Of the geese that survived the first month, 3/5 did not survive the first year.
- This means 3/5 of 1/2 (those who survived first month) i.e. 3/10 did not survive the first year and 2/5 of 1/2 = 1/5 survived the first year.

If 120 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond?
- This means 1/5 calculated above is equal to 120 so total eggs laid were 5*120 = 600.

More often than not, by the time you reach the last statement, most of your question would be already solved.
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Re: PS: goose eggs   [#permalink] 23 Nov 2010, 09:37
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