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Of the mutual funds on a select list, 1/3 have 5-star

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Of the mutual funds on a select list, 1/3 have 5-star [#permalink] New post 06 Oct 2008, 06:38
Of the mutual funds on a “select list,” 1/3 have 5-star ratings, and 2/5 of the remaining funds have 4-star ratings. If the remaining 300 funds on the list have 3-star ratings, how many funds are on the list?

A. 500
B. 750
C. 1,000
D. 1,200
E. 1,500
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Re: Math problem [#permalink] New post 06 Oct 2008, 06:51
albany09 wrote:
Of the mutual funds on a “select list,” 1/3 have 5-star ratings, and 2/5 of the remaining funds have 4-star ratings. If the remaining 300 funds on the list have 3-star ratings, how many funds are on the list?

A. 500
B. 750
C. 1,000
D. 1,200
E. 1,500


5/15+6/15 = 11/15

300 = 3/15x thus x = 1500
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Re: Math problem [#permalink] New post 06 Oct 2008, 23:15
750.

If x is total number of funds then x/3 is the number for 5 star, (2x/3)*2/5 is the number for 4 star.

Total of 5 and 4 start = x/3 + 4x/15 = 9x/15 = 3x/5

Remaining is 2x/5 = 300 and hence, x = 750.
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Re: Math problem [#permalink] New post 07 Oct 2008, 00:57
My two cents:

300=(2/3)*(3/5)*Total

Total=750

B

Which is the OA?

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Re: Math problem [#permalink] New post 07 Oct 2008, 01:23
yes I m also getting B as answer
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Re: Math problem [#permalink] New post 07 Oct 2008, 01:39
I got 1125, can someone show solution of this problem?
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Re: Math problem [#permalink] New post 07 Oct 2008, 02:22
yezz wrote:
albany09 wrote:
Of the mutual funds on a “select list,” 1/3 have 5-star ratings, and 2/5 of the remaining funds have 4-star ratings. If the remaining 300 funds on the list have 3-star ratings, how many funds are on the list?

A. 500
B. 750
C. 1,000
D. 1,200
E. 1,500


5/15+6/15 = 11/15

300 = 3/15x thus x = 1500



Shouldn't it be 4/15? Then x is 1125
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Re: Math problem [#permalink] New post 07 Oct 2008, 02:29
kazakhb wrote:
I got 1125, can someone show solution of this problem?


My post has the steps.
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Re: Math problem [#permalink] New post 07 Oct 2008, 02:40
scthakur wrote:
kazakhb wrote:
I got 1125, can someone show solution of this problem?


My post has the steps.

in your steps you make an assumption that 4star funds are two times 5star funds, but it is not given. is it?
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Re: Math problem [#permalink] New post 08 Oct 2008, 00:50
kazakhb wrote:
scthakur wrote:
kazakhb wrote:
I got 1125, can someone show solution of this problem?


My post has the steps.

in your steps you make an assumption that 4star funds are two times 5star funds, but it is not given. is it?


No. Let us begin all over again.

If x is total number of funds then x/3 is the number for 5 star. Remaining is (x-x/3) = 2x/3.

numer of 4 start funds is 2/5 of the remaining 2x/5 and hence (2x/3)*2/5 is the number for 4 star.

Hope, this clarifies.
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Re: Math problem [#permalink] New post 08 Oct 2008, 01:00
albany09 wrote:
Of the mutual funds on a “select list,” 1/3 have 5-star ratings, and 2/5 of the remaining funds have 4-star ratings. If the remaining 300 funds on the list have 3-star ratings, how many funds are on the list?

A. 500
B. 750
C. 1,000
D. 1,200
E. 1,500


Let X are the total funds, then (1/3)x + (2/3)*(2/5)*x are the 5-star and 4-star funds

x- (1/3)x + (2/3)*(2/5)*x = 300

(9/15) X = 300 and X = 750
ans is "B"
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Re: Math problem [#permalink] New post 08 Oct 2008, 01:08
vivektripathi wrote:
albany09 wrote:
Of the mutual funds on a “select list,” 1/3 have 5-star ratings, and 2/5 of the remaining funds have 4-star ratings. If the remaining 300 funds on the list have 3-star ratings, how many funds are on the list?

A. 500
B. 750
C. 1,000
D. 1,200
E. 1,500


Let X are the total funds, then (1/3)x + (2/3)*(2/5)*x are the 5-star and 4-star funds

x- (1/3)x + (2/3)*(2/5)*x = 300

(9/15) X = 300 and X = 750
ans is "B"


Same answer here (B) for me ! only 2/3*3/5 = 300/x and x=750

:)
Re: Math problem   [#permalink] 08 Oct 2008, 01:08
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