gregspirited wrote:

Of the students who eat in a certain cafeteria, each student either likes or dislikes lima beans and each stident either likes or dislikes brussel sprouts. Of these studenst, 2/3 students dislike lima beans, and of those who dislike lima beans, 3/5 also dislike brussel sprouts. How many of the students like brussel sprouts but dislike lima beans

1. 120 students eat in the cafeteria

2. 40 of the students like lima beans

I think the answer should be D. Any statement should be sufficient .

Question is saying that "

who eat in a certain cafeteria, each student either likes or dislikes lima beans and each stident either likes or dislikes brussel sprouts" ==> Every student must like or dislike Beans & Brussle Spruts.==> It is impossible to have few students who neither like nor dislike Brussl . & who neither like nor dislike Lima beans.

Say total no of Students = x

2/3 of them dislike Lima Beans=2x/3 ==> remaining x/3 must like Beans.

3/5 of 2x/3 dislike Brussle Sprouts = 2x/5( Dislike Lima Beans & Brussle Sprouts)==> Remaing ( 2x/3-2x/5) of 2x/3 should like Brussle Sprouts & Dislike Lema Beans.

Implies 4x/15 students Dislike Lema Beans & Likes Brussle Sprouts.

St 1: says x=120 . SUFF to find the value of 4x/15.

St 2: says x/3 =40 . SUFF to find x and then 4x/15.

So it should be D . anyways ,What is the OA??