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Of the students who eat in a certain cafeteria, each student

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Of the students who eat in a certain cafeteria, each student [#permalink] New post 03 Jun 2010, 23:29
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Of the students who eat in a certain cafeteria, each student either likes or dislikes lima beans and each student either likes or dislikes brussels sprouts. Of these students, 2/3 dislike lima beans; and of those who dislike lima beans, 3/5 also dislike brussels sprouts. How many of the students like brussels sprouts but dislike lima beans?

(1) 120 students eat in the cafeteria
(2) 40 of the students like lima beans
[Reveal] Spoiler: OA

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Re: bowled [#permalink] New post 04 Jun 2010, 02:58
dimitri92 wrote:
What is the best approach to tackle questions like these ?



The question is basically asking how many dislikes Lima beans but like Sprouts..

Given 2/3 of the entire student poplutation dont like LIMA.. of these 3/5 DONT like sprouts..so 2/5 like sprouts..

1) Given total students = 120 so 2/3 * 120 = 80 who dislikes lima beans out of these 2/5* 50 are the ones who likes sprouts but dislikes beans ... Hence Sufficient

2) 40 Likes beans so in thats means 120 is the total number of students... same logic as 1 -- Hence Sufficient

hope this helps..!
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Re: bowled [#permalink] New post 04 Jun 2010, 06:42
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dimitri92 wrote:
What is the best approach to tackle questions like these ?


Of the students who eat in a certain cafeteria, each student either likes or dislikes lima beans and each student either likes or dislikes brussels sprouts. Of these students, 2/3 dislike lima beans; and of those who dislike lima beans, 3/5 also dislike brussels sprouts. How many of the students like brussels sprouts but dislike lima beans?

I'd advise to make a table:
Attachment:
Lima-Sprouts.JPG
Lima-Sprouts.JPG [ 11.66 KiB | Viewed 4158 times ]

Note that:
"2/3 dislike lima beans" means 2/3 of total dislike lima;
"of those who dislike lima beans, 3/5 also dislike brussels sprouts" means of those who dislike lima 1-\frac{3}{5}=\frac{2}{5} like sprout, or \frac{2}{3}*\frac{2}{5}=\frac{4}{15} of total dislike lima but like sprouts. So to calculate # of students who dislike lima but like sprouts we should now total # of students (t).

(1) 120 students eat in the cafeteria --> t=120 --> x=\frac{4}{15}t=32. Sufficient.

(2) 40 of the students like lima beans --> total students who like lima + total students who dislike lima = total --> 40+\frac{2}{3}t=t --> t=120 --> x=\frac{4}{15}t=32. Sufficient.

Answer: D.
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Re: bowled [#permalink] New post 17 Aug 2010, 13:19
Bunuel wrote:
dimitri92 wrote:
What is the best approach to tackle questions like these ?


Of the students who eat in a certain cafeteria, each student either likes or dislikes lima beans and each student either likes or dislikes brussels sprouts. Of these students, 2/3 dislike lima beans; and of those who dislike lima beans, 3/5 also dislike brussels sprouts. How many of the students like brussels sprouts but dislike lima beans?

I'd advise to make a table:
Attachment:
Lima-Sprouts.JPG

Note that:
"2/3 dislike lima beans" means 2/3 of total dislike lima;
"of those who dislike lima beans, 3/5 also dislike brussels sprouts" means of those who dislike lima 1-\frac{3}{5}=\frac{2}{5} like sprout, or \frac{2}{3}*\frac{2}{5}=\frac{4}{15} of total dislike lima but like sprouts. So to calculate # of students who dislike lima but like sprouts we should now total # of students (t).

Answer: D.


I didn't understand this part...
means of those who dislike lima 1-\frac{3}{5}=\frac{2}{5} like sprout, or
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Re: bowled [#permalink] New post 18 Aug 2010, 03:35
Expert's post
onedayill wrote:
Bunuel wrote:
dimitri92 wrote:
What is the best approach to tackle questions like these ?


Of the students who eat in a certain cafeteria, each student either likes or dislikes lima beans and each student either likes or dislikes brussels sprouts. Of these students, 2/3 dislike lima beans; and of those who dislike lima beans, 3/5 also dislike brussels sprouts. How many of the students like brussels sprouts but dislike lima beans?

I'd advise to make a table:
Attachment:
Lima-Sprouts.JPG

Note that:
"2/3 dislike lima beans" means 2/3 of total dislike lima;
"of those who dislike lima beans, 3/5 also dislike brussels sprouts" means of those who dislike lima 1-\frac{3}{5}=\frac{2}{5} like sprout, or \frac{2}{3}*\frac{2}{5}=\frac{4}{15} of total dislike lima but like sprouts. So to calculate # of students who dislike lima but like sprouts we should now total # of students (t).

Answer: D.


I didn't understand this part...
means of those who dislike lima 1-\frac{3}{5}=\frac{2}{5} like sprout, or


If "of those who dislike lima beans, 3/5 (40%) also dislike brussels sprouts", hence rest of of those who dislike lima beans or 2/5 (60%) must like sprouts. As "2/3 of total dislike lima beans" then 2/3*2/5=4/15 of total dislike lima but like sprouts.

Hope it's clear.
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Re: bowled [#permalink] New post 10 Oct 2010, 22:17
D

both 1 and 2 independently tell us what the total number of students is which in turn lets us calculate what is needed in the double-set matrix
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Re: bowled [#permalink] New post 16 Oct 2010, 04:03
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Re: Of the students who eat in a certain cafeteria, each student [#permalink] New post 29 Sep 2013, 08:51
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Re: Of the students who eat in a certain cafeteria, each student [#permalink] New post 01 Oct 2013, 01:12
The answer is D - Both statement are sufficient because we need to find the total number of students. And both the answer choices give us that.
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Need some help with the below question [#permalink] New post 28 Mar 2014, 01:47
Of the students who eat in a certain cafeteria, each student either likes or dislikes Lima beans and each student either likes/dislikes Brussels Sprouts. Of these students, 2/3 dislike Lima Beans and of those who dislike Lima Beans, 3/5 dislike Brussels Sprouts. How many of the students like Brussels Sprouts but dislike Lima Beans?

a. 120 students eat in the cafeteria
b. 40 of the students like Lima beans

OA is D. Please help.
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Re: Need some help with the below question [#permalink] New post 28 Mar 2014, 01:51
Expert's post
sudeeptasahu29 wrote:
Of the students who eat in a certain cafeteria, each student either likes or dislikes Lima beans and each student either likes/dislikes Brussels Sprouts. Of these students, 2/3 dislike Lima Beans and of those who dislike Lima Beans, 3/5 dislike Brussels Sprouts. How many of the students like Brussels Sprouts but dislike Lima Beans?

a. 120 students eat in the cafeteria
b. 40 of the students like Lima beans

OA is D. Please help.


Merging similar topics. Please refer to the discussion above.

P.S. PLEASE name the topics properly. Rule #3 here: rules-for-posting-please-read-this-before-posting-133935.html


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PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: Need some help with the below question   [#permalink] 28 Mar 2014, 01:51
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