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Of the students who eat in a certain cafeteria, each student [#permalink]
03 Jun 2010, 23:29

2

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

65% (hard)

Question Stats:

65% (02:09) correct
35% (01:56) wrong based on 104 sessions

Of the students who eat in a certain cafeteria, each student either likes or dislikes lima beans and each student either likes or dislikes brussels sprouts. Of these students, 2/3 dislike lima beans; and of those who dislike lima beans, 3/5 also dislike brussels sprouts. How many of the students like brussels sprouts but dislike lima beans?

(1) 120 students eat in the cafeteria (2) 40 of the students like lima beans

What is the best approach to tackle questions like these ?

The question is basically asking how many dislikes Lima beans but like Sprouts..

Given 2/3 of the entire student poplutation dont like LIMA.. of these 3/5 DONT like sprouts..so 2/5 like sprouts..

1) Given total students = 120 so 2/3 * 120 = 80 who dislikes lima beans out of these 2/5* 50 are the ones who likes sprouts but dislikes beans ... Hence Sufficient

2) 40 Likes beans so in thats means 120 is the total number of students... same logic as 1 -- Hence Sufficient

What is the best approach to tackle questions like these ?

Of the students who eat in a certain cafeteria, each student either likes or dislikes lima beans and each student either likes or dislikes brussels sprouts. Of these students, 2/3 dislike lima beans; and of those who dislike lima beans, 3/5 also dislike brussels sprouts. How many of the students like brussels sprouts but dislike lima beans?

I'd advise to make a table:

Attachment:

Lima-Sprouts.JPG [ 11.66 KiB | Viewed 4339 times ]

Note that: "2/3 dislike lima beans" means 2/3 of total dislike lima; "of those who dislike lima beans, 3/5 also dislike brussels sprouts" means of those who dislike lima1-\frac{3}{5}=\frac{2}{5} like sprout, or \frac{2}{3}*\frac{2}{5}=\frac{4}{15} of total dislike lima but like sprouts. So to calculate # of students who dislike lima but like sprouts we should now total # of students (t).

(1) 120 students eat in the cafeteria --> t=120 --> x=\frac{4}{15}t=32. Sufficient.

(2) 40 of the students like lima beans --> total students who like lima + total students who dislike lima = total --> 40+\frac{2}{3}t=t --> t=120 --> x=\frac{4}{15}t=32. Sufficient.

What is the best approach to tackle questions like these ?

Of the students who eat in a certain cafeteria, each student either likes or dislikes lima beans and each student either likes or dislikes brussels sprouts. Of these students, 2/3 dislike lima beans; and of those who dislike lima beans, 3/5 also dislike brussels sprouts. How many of the students like brussels sprouts but dislike lima beans?

I'd advise to make a table:

Attachment:

Lima-Sprouts.JPG

Note that: "2/3 dislike lima beans" means 2/3 of total dislike lima; "of those who dislike lima beans, 3/5 also dislike brussels sprouts" means of those who dislike lima1-\frac{3}{5}=\frac{2}{5} like sprout, or \frac{2}{3}*\frac{2}{5}=\frac{4}{15} of total dislike lima but like sprouts. So to calculate # of students who dislike lima but like sprouts we should now total # of students (t).

Answer: D.

I didn't understand this part... means of those who dislike lima1-\frac{3}{5}=\frac{2}{5} like sprout, or _________________

GGG (Gym / GMAT / Girl) -- Be Serious

Its your duty to post OA afterwards; some one must be waiting for that...

What is the best approach to tackle questions like these ?

Of the students who eat in a certain cafeteria, each student either likes or dislikes lima beans and each student either likes or dislikes brussels sprouts. Of these students, 2/3 dislike lima beans; and of those who dislike lima beans, 3/5 also dislike brussels sprouts. How many of the students like brussels sprouts but dislike lima beans?

I'd advise to make a table:

Attachment:

Lima-Sprouts.JPG

Note that: "2/3 dislike lima beans" means 2/3 of total dislike lima; "of those who dislike lima beans, 3/5 also dislike brussels sprouts" means of those who dislike lima1-\frac{3}{5}=\frac{2}{5} like sprout, or \frac{2}{3}*\frac{2}{5}=\frac{4}{15} of total dislike lima but like sprouts. So to calculate # of students who dislike lima but like sprouts we should now total # of students (t).

Answer: D.

I didn't understand this part... means of those who dislike lima1-\frac{3}{5}=\frac{2}{5} like sprout, or

If "of those who dislike lima beans, 3/5 (40%) also dislike brussels sprouts", hence rest of of those who dislike lima beans or 2/5 (60%) must like sprouts. As "2/3 of total dislike lima beans" then 2/3*2/5=4/15 of total dislike lima but like sprouts.

both 1 and 2 independently tell us what the total number of students is which in turn lets us calculate what is needed in the double-set matrix _________________

Re: Of the students who eat in a certain cafeteria, each student [#permalink]
29 Sep 2013, 08:51

Hello from the GMAT Club BumpBot!

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Need some help with the below question [#permalink]
28 Mar 2014, 01:47

Of the students who eat in a certain cafeteria, each student either likes or dislikes Lima beans and each student either likes/dislikes Brussels Sprouts. Of these students, 2/3 dislike Lima Beans and of those who dislike Lima Beans, 3/5 dislike Brussels Sprouts. How many of the students like Brussels Sprouts but dislike Lima Beans?

a. 120 students eat in the cafeteria b. 40 of the students like Lima beans

Re: Need some help with the below question [#permalink]
28 Mar 2014, 01:51

Expert's post

sudeeptasahu29 wrote:

Of the students who eat in a certain cafeteria, each student either likes or dislikes Lima beans and each student either likes/dislikes Brussels Sprouts. Of these students, 2/3 dislike Lima Beans and of those who dislike Lima Beans, 3/5 dislike Brussels Sprouts. How many of the students like Brussels Sprouts but dislike Lima Beans?

a. 120 students eat in the cafeteria b. 40 of the students like Lima beans

OA is D. Please help.

Merging similar topics. Please refer to the discussion above.