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I suppose case 2 u have taken is wrong...try out for female=99 so A becomes INSUFF

Silly type in my post. I meant f = 99, but typed as m=99. I have corrected in my post. A will still be sufficient.

I thought so at first too. But if you plugged in let's say 100 for boys and 200 for girls, and then tried plugging in 100 for girls and 20 boys, you'd see that A is insuff. Therefore B is always sufficient, doesn't matter what no's you plug in

I suppose case 2 u have taken is wrong...try out for female=99 so A becomes INSUFF

Silly type in my post. I meant f = 99, but typed as m=99. I have corrected in my post. A will still be sufficient.

you need to look at extreme cases in these type of questions, say if the number of girls approaches infinity, then the number of boys is insignificant..which means that over all avg will approach 55%

I thought so at first too. But if you plugged in let's say 100 for boys and 200 for girls, and then tried plugging in 100 for girls and 20 boys, you'd see that A is insuff. Therefore B is always sufficient, doesn't matter what no's you plug in

Now, I have a hard time trying to analyze it.

For stmt2: say f = 21, m = 1 and total = 22. In this case, percentage will be less than 50. And if, f = 200 and m = 180 and total = 380 then in this case, percentage will be > 50. HEnce, I feel B is insufficient.

I thought so at first too. But if you plugged in let's say 100 for boys and 200 for girls, and then tried plugging in 100 for girls and 20 boys, you'd see that A is insuff. Therefore B is always sufficient, doesn't matter what no's you plug in

Now, I have a hard time trying to analyze it.

For stmt2: say f = 21, m = 1 and total = 22. In this case, percentage will be less than 50. And if, f = 200 and m = 180 and total = 380 then in this case, percentage will be > 50. HEnce, I feel B is insufficient.

Of the total student in a class, 55% of female and 35% of male passed an exam. Did more than half of the student in the class passed the exam?

A - More than half of students in class are female B - The number of female 20 more than number of male students.

I think it's B; Although the extreme example F=21, M=1 would prove B invalid, I think this example is invalid because the class must have at least 20 males (since 35% of males pass the exam, we can't have 0.35 of 1 male passing an exam)

Statement 1: If F=1000, M=20, then more than half passed (557/1020 TRUE) If F=60, M=40, then fewer than half passed (47/100, FALSE) insufficient

Statement 2: If F=10020, M=10000, then fewer then half passed (5511+3500/20020 FALSE) If F=40, M=20, then fewer than half passed ((22+7)/60, still FALSE at best possible case) Sufficient

Of the total student in a class, 55% of female and 35% of male passed an exam. Did more than half of the student in the class passed the exam?

A - More than half of students in class are female B - The number of female 20 more than number of male students. ----------- I got B,

stmt 1) try to forced # to be 100 then if F=60 and M=40 then only 47 students pass exam --> No but if F=80, M=20, then student pass is 51 ---> yes so stmt 1) insuff

stmt 2) F=M+20 then 0.35M+0.55F > 0.5(F+M) 0.05F > 0.15M F > 3M M+20 > 3M 10>M then if M < 10, more than half of student will pass the exam

A - INSUFF, as we all got this one B - number female Y then number of male Y-20

%student who pass the exam: [0.55Y+0.35(Y-20)]/(2Y-20)=(0.9Y-7)/(2Y-20) if (0.9Y-7)/(2Y-20)>0.5 then Y should be >130, so Y can be any value so INSUFF

Didn't get the explanation of B - please pitch in!

Look at it the other way. The question does not say anywhere that y > 130. Thus, y can be 50, 100 or even 200. If y is less than or equal to 130, (0.9Y-7)/(2Y-20)>0.5 will not be true.