Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

OG 12th edition sqrt problem [#permalink]
12 Nov 2009, 05:04

#32 on page 156 has a rather simple sqrt problem, which I am able to solve using a brute force method for finding the sqrt. However, I'd like to understand the book's solution for finding the solution more quickly, but don't quite follow it. Any help would be appreciated.

I've attached an image showing the book's solution. I'm wondering how I am able to drop the 16 as one of the root multiples of 256 (the product of 8*32).

Appreciate any help!

Attachments

sqrt_problem.png [ 182.14 KiB | Viewed 3006 times ]

Re: OG 12th edition sqrt problem [#permalink]
12 Nov 2009, 05:17

Expert's post

The solution in book is quite strange. Generally \(\sqrt{a+b}\), DOES NOT equal to \(\sqrt{a}+\sqrt{b}\). Example: \(\sqrt{16+16}=\sqrt{32}=4*\sqrt{2}\) and NOT \(\sqrt{16}+\sqrt{16}=4+4=8\).

Back to the question:

As I understand the problem is:

\(\sqrt{16*20+8*32}\) if yes then: \(\sqrt{16*(20+8*2)}=\sqrt{16*36}=4*6=24\)

Re: OG 12th edition sqrt problem [#permalink]
12 Nov 2009, 07:24

Argh. Sorry, there is a typo in my image - you are correct that it should be \(\sqrt{16}*\sqrt{36}\) and not \(\sqrt{16}+\sqrt{36}\).

I am embarrassed that I still do not understand how (8*32) becomes (8*2)? 8*32 is 256, the root of which is 16. So by my thinking, that would leave me with \(\sqrt{(16)(20)+(16)(16)}\). How do you get \(\sqrt{(16)(20)+(8)(2)}\) from that?

Re: OG 12th edition sqrt problem [#permalink]
12 Nov 2009, 07:42

1

This post received KUDOS

Expert's post

capable2 wrote:

Argh. Sorry, there is a typo in my image - you are correct that it should be \(\sqrt{16}*\sqrt{36}\) and not \(\sqrt{16}+\sqrt{36}\).

I am embarrassed that I still do not understand how (8*32) becomes (8*2)? 8*32 is 256, the root of which is 16. So by my thinking, that would leave me with \(\sqrt{(16)(20)+(16)(16)}\). How do you get \(\sqrt{(16)(20)+(8)(2)}\) from that?

Thanks again.

The red part is not correct we'll get not the expression you wrote but: \(\sqrt{16*(20+8*2)}\). Look at the brackets.

And here is how:

Let's just forget about the square root for a moment. We have:

\(16*20+8*32\) no need to multiply \(8\) by \(32\), it's a long way, though still correct. Just take \(16\) from the brackets:

Re: OG 12th edition sqrt problem [#permalink]
30 Jan 2012, 01:23

Expert's post

joshuaRome wrote:

Hello everyone,

I am having some difficulty with this problem similar to the author of this post.

My problem (and possibly flawed logic):

It is my understanding that \sqrt{2}+\sqrt{2}=2\sqrt{2} and that adding square roots produces the wrong answer.

to say that \sqrt{2}+\sqrt{2}=\sqrt{4}=2 is incorrect from what i see. (1.4appx+1.4appx is not 2)

problem 32 OG:

sqrt{ 16 (20 + 8 * 2)}

sqrt{ 16 (20 + 16)} okay we factored out 16, makes sense to me...

sqrt{16 (36)}

i don't see how we can add two square roots together. square root of 20 + square root 16 is 8.47 not 6.

Thank you for any responses! I know I must have made a mistake but sometimes a different perspective can help.

The point is that we are not adding square root of 20 and square root of 16, we are adding 20 and 16 under the SAME square root. Below it he solution to the problem from OG:

\(\sqrt{16*20+8*32}=?\) --> factor out 16: \(\sqrt{16(20+8*2)}=\sqrt{16*36}=4*6=24\).

Re: OG 12th edition sqrt problem [#permalink]
15 Nov 2014, 15:45

Bunuel wrote:

joshuaRome wrote:

Hello everyone,

I am having some difficulty with this problem similar to the author of this post.

My problem (and possibly flawed logic):

It is my understanding that \sqrt{2}+\sqrt{2}=2\sqrt{2} and that adding square roots produces the wrong answer.

to say that \sqrt{2}+\sqrt{2}=\sqrt{4}=2 is incorrect from what i see. (1.4appx+1.4appx is not 2)

problem 32 OG:

sqrt{ 16 (20 + 8 * 2)}

sqrt{ 16 (20 + 16)} okay we factored out 16, makes sense to me...

sqrt{16 (36)}

i don't see how we can add two square roots together. square root of 20 + square root 16 is 8.47 not 6.

Thank you for any responses! I know I must have made a mistake but sometimes a different perspective can help.

The point is that we are not adding square root of 20 and square root of 16, we are adding 20 and 16 under the SAME square root. Below it he solution to the problem from OG:

\(\sqrt{16*20+8*32}=?\) --> factor out 16: \(\sqrt{16(20+8*2)}=\sqrt{16*36}=4*6=24\).

I just have one question, wouldn't there still be a 1 left over when you factor out the 16? I'm just thinking if you were to reverse the operation, what would the 16 get multiplied into? _________________

"Popular opinion is the greatest lie in the world"-Thomas Carlyle

Re: OG 12th edition sqrt problem [#permalink]
17 Nov 2014, 11:23

Expert's post

Bigred2008 wrote:

Bunuel wrote:

joshuaRome wrote:

Hello everyone,

I am having some difficulty with this problem similar to the author of this post.

My problem (and possibly flawed logic):

It is my understanding that \sqrt{2}+\sqrt{2}=2\sqrt{2} and that adding square roots produces the wrong answer.

to say that \sqrt{2}+\sqrt{2}=\sqrt{4}=2 is incorrect from what i see. (1.4appx+1.4appx is not 2)

problem 32 OG:

sqrt{ 16 (20 + 8 * 2)}

sqrt{ 16 (20 + 16)} okay we factored out 16, makes sense to me...

sqrt{16 (36)}

i don't see how we can add two square roots together. square root of 20 + square root 16 is 8.47 not 6.

Thank you for any responses! I know I must have made a mistake but sometimes a different perspective can help.

The point is that we are not adding square root of 20 and square root of 16, we are adding 20 and 16 under the SAME square root. Below it he solution to the problem from OG:

\(\sqrt{16*20+8*32}=?\) --> factor out 16: \(\sqrt{16(20+8*2)}=\sqrt{16*36}=4*6=24\).

I just have one question, wouldn't there still be a 1 left over when you factor out the 16? I'm just thinking if you were to reverse the operation, what would the 16 get multiplied into?

You mean it should be \(\sqrt{16(20*1+8*2)}=\sqrt{16*36}=4*6=24\)? Yes, but 20*1 = 20, so we can omit 1 there.

Michigan Ross: Center for Social Impact : The Center for Social Impact provides leaders with practical skills and insight to tackle complex social challenges and catalyze a career in...

The Importance of Financial Regulation : Before immersing in the technical details of valuing stocks, bonds, derivatives and companies, I always told my students that the financial system is...

The following pictures perfectly describe what I’ve been up to these days. MBA is an extremely valuable tool in your career, no doubt, just that it is also...