Does y=3x+2 contain (r,s)?

It is C.

Statement 1: (3r+2-s)(4r+9-s)=0

So either (3r+2-s) = 0 or (4r+9-s)=0

If 3r+2-s =0

ie s= 3r+2 which mean y=3x+2 contain (r,s)

But if (4r+9-s) =0 then y=3x+2 does not contain (r,s).

So (1) is not sufficient.

Statement 2: (4r-6-s)(3r+2-s) = 0

Thinking along the same lines (2) is not sufficient.

If we combine both (3r+2-s) must be 0

Hence the line contains (r,s)

So it is C

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