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# Oil cans x and y are right circular cylinders and the height

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Oil cans x and y are right circular cylinders and the height [#permalink]  17 Feb 2007, 14:25
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Difficulty:

25% (medium)

Question Stats:

67% (01:48) correct 33% (00:47) wrong based on 114 sessions
Oil cans x and y are right circular cylinders and the height and radius of y are each twice those of x. If the oil in can x filled to capacity sells for $2, how much does the oil in y sell for if y is only half filled? A$1
B $2 C$3
D $4 E$8
[Reveal] Spoiler: OA

Last edited by Bunuel on 06 Mar 2012, 04:36, edited 1 time in total.
Edited the question
Intern
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Volume of x(Vx) is r^2*PI*h (r-radius, h height)

Volume of y (Vy) is (2r)^2*PI*2h = 4*r^2*PI*2h=8r^2*PI*h = 8*Vx

If Vx is 2$Vy/2=4*Vx=8$
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Re: Volume [#permalink]  17 Feb 2007, 20:28
cucrose wrote:
Oil cans x and y are right circular cylinders and the height and radius of y are each twice those of x. If the oil in can x filled to capacity sells for $2, how much does the oil in y sell for if y is only half filled? A$1
B $2 C$3
D $4 E$8

Can someone please explain this one? thanks.

formula for vol of a cyl is PI*r^2*h

so Vy = 8*Vy

y when half filled will cost 4 times x so ans is E
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Re: Volume [#permalink]  05 Mar 2012, 22:28
can you help me,where are you getting 8 since volume of y is on 2r *Pi*2h,as stated on the question?

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Re: Volume [#permalink]  06 Mar 2012, 04:35
Expert's post
Andrew222 wrote:
can you help me,where are you getting 8 since volume of y is on 2r *Pi*2h,as stated on the question?

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Welcome to GMAT Club. Below is a complete step-by-step solution of the question.

Oil cans x and y are right circular cylinders and the height and radius of y are each twice those of x. If the oil in can x filled to capacity sells for $2, how much does the oil in y sell for if y is only half filled? A$1
B $2 C$3
D $4 E$8

The volume of can X is \pi{r^2}h, which when filled to capacity sells for $2; The volume of can Y is \pi{(2r)^2}(2h)=8\pi{r^2}h. Can Y is only half fill so volume of oil in it is 4\pi{r^2}h. Since \pi{r^2}h sells for$2 then 4\pi{r^2}h sells for 4*$2=8$.

Hope its clear.
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Re: Oil cans x and y are right circular cylinders and the height [#permalink]  16 Mar 2012, 00:24
Thank you i can now get you what you were doing to get the answer

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Re: Oil cans x and y are right circular cylinders and the height   [#permalink] 16 Mar 2012, 00:24
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