Ok, I'm probably going to be embarassed by how easy this is, : Quant Question Archive [LOCKED]
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# Ok, I'm probably going to be embarassed by how easy this is,

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Director
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Ok, I'm probably going to be embarassed by how easy this is, [#permalink]

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13 Sep 2006, 07:31
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Ok, I'm probably going to be embarassed by how easy this is, but if I don't ask, I'll never learn.

Can't write this properly in this format - but what is: the cube root of the square root of x to the 48th power?? And please show me how you worked the problem.

Thanks so much.
-Mary
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Re: Recent GMAT question - help! [#permalink]

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13 Sep 2006, 07:57
uphillclimb wrote:
Ok, I'm probably going to be embarassed by how easy this is, but if I don't ask, I'll never learn.

Can't write this properly in this format - but what is: the cube root of the square root of x to the 48th power?? And please show me how you worked the problem.

Thanks so much.
-Mary

translating english to math: cube root = 1/3 power, square root = 1/2 power,

so ((x^1/2)^48)^1/3. You can multiply the powers (1/2 * 48 * 1/3) =8, so it's x^8
Director
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13 Sep 2006, 08:00
Ooooooooh.
Thank you!
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13 Sep 2006, 08:11
(((X^48)^(1/2))^(1/3)) = X^(48*1/2*1/3) = x^8
13 Sep 2006, 08:11
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